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Alenkasestr [34]
3 years ago
12

The table below shows the distance d(t) in feet that an object travels in t seconds: t (seconds) d(t) (feet) 1 15 2 60 3 135 4 2

40 What is the average rate of change of d(t) between 2 seconds and 4 seconds, and what does it represent?
50 ft/s; it represents the average speed of the object between 2 seconds and 4 seconds
90 ft/s; it represents the average speed of the object between 2 seconds and 4 seconds
90 ft/s; it represents the average distance traveled by the object between 2 seconds and 4 seconds
50 ft/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds
Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer:


Step-by-step explanation:

Answer:


Option B is correct


The average rate of change of d(t) between 2 second and 4 second is; 90 ft/s


and it represents the average speed of the object between 2 seconds and 4 seconds.


Step-by-step explanation:


Average rate of change of function is defined as the ratio of the difference in the function f(x) as it changes from a to b to the difference between a and b. Then, the average rate of change is denoted as A(x).




As per the given statement, the distance d(t) is in feet and t is the time in second.


To find the average rate of change of d(t) between 2 seconds and 4 seconds.


From the table we have;


at t = 2 , d(2) = 60


and


at t =4 , d(4) = 240.


Then, by the definition of average rate of change ;


=


Simplify:




therefore, the average rate of change of d(t) between 2 second and 4 second is; 90 ft/s and it represents the average speed of the object between 2 seconds and 4 seconds.




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