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7nadin3 [17]
3 years ago
12

What is the importance of DNA copying in reproduction ?​

Mathematics
1 answer:
slava [35]3 years ago
6 0

Answer:

DNA copying is an essential part of the process of reproduction because it carries the genetic information from the parents to offspring. A copy of DNA is produced through some chemical reactions resulting in two copies of DNA.

Step-by-step explanation:

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Please help with this math question
vodka [1.7K]
The answer is zach on Monday
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5 0
3 years ago
Determine the value of the ?
goblinko [34]

Answer:

x^{2} y^{3}

Step-by-step explanation:

Using the Quotient rule:

\frac{a^{m}}{a^{n}} = a^{m - n}

We can subtract the exponents of x and y:

\frac{x^{6} y^{10}}{x^{4} y^{7}} = x^{(6 - 4)} y^{(10 - 7)}

Therefore, \frac{x^{6} y^{10}}{x^{4} y^{7}} = x^{2} y^{3}

Please mark my answers as the Brainliest if you find this explanation helpful :)

5 0
2 years ago
What is the exact value of the exponential equation, 4(10)5x=200 ?
Rasek [7]

Answer:

4(10)5x=200 = x=log50 / 5

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Work out the circumference of this circle.
Arada [10]

Answer: 52.7856cm

Step-by-step explanation:

Circumference of a circle = 2πr

Note that radius = Diameter / 2 = 16.8/2 = 8.4cm

Circumference = 2πr

= 2 × 3.142 × 8.4

= 52.7856cm

Therefore, the circumference of the circle is 52.7856cm

6 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
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