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finlep [7]
3 years ago
10

The measure of each angle of an equiangular triangle is

Mathematics
2 answers:
MrRissso [65]3 years ago
7 0
C. This is because if it is an equiangular triangle this means that all the angles have the same angle. You know that all the angles in a triangle add up to 180 degrees? You just divided 180 by 3 as there are three angles in a triangle. Which gives you 60 degrees.
liberstina [14]3 years ago
7 0

equiangular triangle ⇒ All angles are equal in measurement


180 ÷ 3 = 60°


Answer: Each angle is 60° (C)

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How many times greater is 3 x 10^8 than 6 x 10^5​
Yuliya22 [10]

Answer:

500

Step-by-step explanation:

3 x 10^8 /6 x 10^5​ = 500

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3 years ago
Which is the simplified form of this expression? <br><br> (2x+3) (x-6)-2x^2+3x+30
docker41 [41]
-6x + 12

To find this answer, follow these steps:

First, multiply 2x + 3 and x - 6 using either the FOIL method or the box method. This should get you the answer of 2x^2 - 9x - 18

This should now replace the 2x + 3 and x - 6

So with that, you should have this currently:

2x^2 - 9x - 18 - 2x^2 + 3x + 30

Now, combine like terms:

The 2x^2 cancels each other out. After that, combine -9x and 3x to get -6x. Then -18 and 30.

This should leave you with the final answer of -6x + 12

Hope this helps!
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LMNP is rotated 90° clockwise around the origin.<br> What are the coordinates of P'?
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Because of safety considerations, the FAA changed its guidelines for how small commuter airlines must estimate passenger weights
Alchen [17]

Answer:

t=\frac{190-180}{\frac{23}{\sqrt{100}}}=4.348    

df=n-1=100-1=99  

p_v =2*P(t_{(99)}>4.348)=0.000033  

Since the p value obtained for this case is a very low value we have enough evidence to reject the null hypothesis that the true mean is equal to 180 at many of the possible significance levels commonly used.  So then makes sense the claim that the true mean for the weigth is different from 180

Step-by-step explanation:

Information provided

\bar X=190 represent the mean weight

s=23 represent the sample standard deviation for the weight

n=100 sample size  

\mu_o =180 represent the value to compare

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to determine if the true mean weight is different from 180 pounds, the system of hypothesis would be:  

Null hypothesis:\mu = 180  

Alternative hypothesis:\mu \neq 180  

We don't know the population deviation for the variable of interest so then the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the data given we got:

t=\frac{190-180}{\frac{23}{\sqrt{100}}}=4.348    

Now we can find the p value but first we need to find the degrees of freedom given by:

df=n-1=100-1=99  

Since we are conducting a two tailed test the p value can be calculated on this way:

p_v =2*P(t_{(99)}>4.348)=0.000033  

Since the p value obtained for this case is a very low value we have enough evidence to reject the null hypothesis that the true mean is equal to 180 at many of the possible significance levels commonly used.  So then makes sense the claim that the true mean for the weigth is different from 180

4 0
3 years ago
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