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3 years ago

| 15. Write an equation and solve.

Mathematics

1 answer:

docker41 [41]3 years ago

4 0

Answer:

The value x in the equation 50=14+x+7+2x-1 is 10

Step-by-step explanation:

Given that the length of one side of a triangle is 14 inches

Let a be the length of one side

Therefore a=14 inches

The length of second side in x+7 inches

Let b be the length of second side

b=x+7 inches.

The length of third side is 2x-1 inches

Let c be the length of third side

c=2x-1 inches

And perimeter of the triangle =50 inches

Perimeter of a triangle =a+b+c

Equation can be written as

50=14+x+7+2x-1

50=20+3x ( adding the like terms )

Rewritting as below

3x+20=50

3x+20-50=50-50

3x-30=0

3x-30+30=0+30

3x=30

$x=\frac{30}{3}$

Therefore x=10

The value of x is 10

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For a quadratic of the form $f(x)=ax^2+bx+c$ , we have the quadratic formula
$x=\dfrac{-b \pm \sqrt{b^2 -4ac} }{2a}$ ,
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given $2x^2-16x+27=0$ , we can get that $a=2, \ b=-16$ , and $c=27$ . We substitute these numbers into the quadratic formula above.

$x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}$

$x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}$

$x=\dfrac{16 \pm \sqrt{40} }{4}$

$x=\dfrac{16 \pm 2\sqrt{10} }{4}$

$x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}$

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the $\pm$ symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.