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PolarNik [594]
2 years ago
5

A store sold 28 boxes of juice from a case containing 48 boxes. Approximately what percent of the case of juice has been sold?

Mathematics
2 answers:
yan [13]2 years ago
5 0

Answer: 58.33 %

Step-by-step explanation:

To find the percentage sold;

Number sold / Total number ×100%

number sold = 28

total number = 48

percentage sold = 28|48 × 100%

Percentage sold = 28 × 100 / 48

percentage sold = 2800/48

= 58.33%

iVinArrow [24]2 years ago
3 0
<span>58.3333333333%
.................................</span>
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Solve 5(2^x+4)=15 round to the nearest thousandth
Novosadov [1.4K]

Answer:

Step-by-step explanation:

Begin by dividing by 5

2x + 4 = 3            

Is this written as 2^(x + 4) = 3? I think it is.

Take the log of both sides

log 2^(x + 4) = log(3)

(x + 4) * log(2) = log 3

log 2 = 0.30103

log 3 = 0.47712

(x + 4) = log2 / log3

x + 4 = 0.63093               Add 4 to both sides

x = -3.369                        Rounded to the nearest thousandth

====================

If you mean the question exactly as it is written (the 4 is not part of the power)

5(2^x + 4) = 15

2^x + 4 = 3

2^x = 3 - 4

2^x = - 1

This can't be done 2 to any power should be >0.

if x>0 then this will give an ever increasing number

if xK0 then this will give an ever decreasing answer but still greater than 0.

No value will make 2^x go to something minus.

If I have misread this in some way, leave a note and I will get back to you.

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2 years ago
Seventy-five students were in the audience
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Tpy6a [65]

5/6 - 3/8

Rewrite the fractions to have a common denominator:

5/6 x 4 = 20/24

3/8 x 3 = 9/24

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Read 2 more answers
Complete the proofs using the most appropriate method. may require CPCTC.
n200080 [17]

For the first one, you did good. I will just suggest a couple things.

Statement              Reason

JK ≅ LM                   Given

<JKM ≅ < LMK        Given  (You did both of these steps so well done.)

MK ≅ MK              Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)

ΔJMK ≅ ΔLKM        SAS

Problem 2: (You also have a lot of great stuff here.)

Statement          Reason

DE ║ FG              Given

DE ≅ FG              Given

<DEF≅<FGH       Given

<EDF≅<GFH       Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)

ΔEDF≅ΔGFH        ASA

<DFE≅<FHG       CPCTC  

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