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siniylev [52]
3 years ago
8

Explain when the median of a data set is a better measure of center than the mean.

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

The median of a data set is better when you have a term or terms that are not close to the other terms

Step-by-step explanation:

For example:

Say you have the data set

1, 15, 17, 18, 22, 84

The median of these terms would be 17.5

       (it is the exact center of the data group)

17 + 18 = 35

35/2 = 17.5

The mean of these terms would be 26.17  

    (this number is not close to the center because the numbers 1 and 84

      are not close enough to the other terms)

1 + 15 + 17 + 18 + 22 + 84 = 157

157/6 = 26.17

AVprozaik [17]3 years ago
3 0

Answer:

Sample Response: When there is an outlier in the data set, the dot plot or histogram will be skewed. In a skewed representation, the mean is pulled up or down toward the tail of the data. Therefore, skewed data affects the mean more than the median.

What did you include in your response? Check all that apply.

The dot plot or histogram will be skewed.

The mean is pulled up or down toward the tail.

The mean is affected more than the median.

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Help plz i’ll give extra points
swat32

elevation in feet = 8.56(140) + 674

elevation in feet = 1872.4

Round to the nearest whole number: 1872

Answer: 1872

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3 years ago
Guyys!! Im helping my lil sister here but I completely forgot it?
iren [92.7K]

Answer:B:72


Step-by-step explanation:

Because you are doing multiplication and division in this problem

5 0
3 years ago
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
Which is the answer ?
erik [133]

Answer:

(a) y = ±(√x)/2

Step-by-step explanation:

You want to find y such that ...

x = f(y)

x = 4y^2 . . . . . . . put in the expression for f(y)

x/4 = y^2 . . . . . . .divide by 4

±√(x/4) = y . . . . . take the square root

y = ±(√y)/2 . . . . . simplify

4 0
2 years ago
The three angles of a quadrilaterals are 540, 970,860.Find the fourth angle?
m_a_m_a [10]

Answer:123 degrees

Step-by-step explanation:

360-54-97-86=123

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2 years ago
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