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77julia77 [94]
2 years ago
7

If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth af

ter 15 years?
Round your answer to the nearest dollar.
Do NOT round until you have calculated the final answer.

Answer 5327
Mathematics
1 answer:
zalisa [80]2 years ago
3 0

Answer:

$5327

Step-by-step explanation:

Use the formula for calculating compound interest

A(t)=P(1+r/n)^n⋅t,

where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find

A(t)=P(1+r/n)^n⋅t = $3,900(1+0.0211)^(15)(1) ≈ $5,326.61

So the final answer is $5,327.

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3 times x minus 2/5 =8/5 what is x equal to
shutvik [7]

Translating this word problem into an algebraic equation, we get:

3x - 2/5 = 8/5.

Let's combine the constants:  adding 2/5 to both sides of this equation yields  

3x = 10/5, or 3x = 2.

Solving for x:  x = 2/3

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3 years ago
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Bezzdna [24]
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2 years ago
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Talja [164]

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3 years ago
$300 at 6% for 3 years
Charra [1.4K]
Its I=prt 
so plug it in
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now its basic multiplying
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schepotkina [342]

Answer:

There are infinitely many solutions

Step-by-step explanation:

Firstly, I need to change f to x as the system won’t accept the word f

Let’s take a look at the question;

3 is less than x

The domain of our answer lies in the the range of values where we have numbers that are greater than 3

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This makes us have infinitely many solutions for the value of x

6 0
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