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77julia77 [94]
3 years ago
7

If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth af

ter 15 years?
Round your answer to the nearest dollar.
Do NOT round until you have calculated the final answer.

Answer 5327
Mathematics
1 answer:
zalisa [80]3 years ago
3 0

Answer:

$5327

Step-by-step explanation:

Use the formula for calculating compound interest

A(t)=P(1+r/n)^n⋅t,

where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find

A(t)=P(1+r/n)^n⋅t = $3,900(1+0.0211)^(15)(1) ≈ $5,326.61

So the final answer is $5,327.

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Answer:

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Step-by-step explanation:

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Swimmer does  2 miles in 40 minutes then he does

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We get the following system:

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Solving the system

From equation (1)

20*Vp  +  20* Vw  =  1       ⇒     Vw  =  ( 1 - 20*Vp ) /20

Plugging that value in the second equation

(Vp  - Vw )* 30  = 1      ⇒  [ Vp - ( 1 - 20*Vp )/20 ] * 30  = 1

[20*Vp - 1 + 20*Vp ] * 30/20 = 1     ⇒ [ 40*Vp - 1 ] *30  =  20     or

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Vp  =  5 / 120 miles/min    or  

Vp = 1 / 24  miles/min

and speed of water   Vw  =  1 / 120

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Answer:

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Step-by-step explanation:

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