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notsponge [240]
3 years ago
13

What are the zeros of the function: f(x) = 2x^2-50

Mathematics
2 answers:
Veronika [31]3 years ago
5 0
Zeros is a value of x when y, or f(x)=0
2x²-50=0
2(x²-25)=0
2(x-5)(x+5)=0
x-5=0
x+5=0
x1=5, x2=-5
zeros are 5 and -5
yan [13]3 years ago
3 0
When f(x) = 0, 

2x^2 - 50 = 0

2(x^2 - 25) = 0

2(x- 5)(x + 5) = 0

(x - 5) = 0 \ or  \ (x + 5) = 0

x = 5 \ or \ x = -5

--------------------------------
Answer : x = 5 or -5
--------------------------------

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Read 2 more answers
8+—3(6+—6a) help please
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and:

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if you have solve for a then:

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5 0
2 years ago
Given: m∠EYL=72°<br> Find: mEHL , mLVE
White raven [17]

Answer:

Part 1) The measure of arc EHL is 108\°

Part 2) The measure of angle LVE is 54\°

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

m

we have

m

substitute

72\°=\frac{1}{2}(y-x)

144\°=(y-x)

y=144\°+x ------> equation A

Remember that

x+y=360\° -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

x+(144\°+x)=360\°

2x=360\°-144\°

x=216\°/2=108\°

Find the value of y

y=144\°+x

y=144\°+108\°=252\°

therefore

The measure of arc EHL is 108\°

The measure of arc EVL is 252\°

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

m

we have

x=108\°

substitute

m

3 0
3 years ago
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Answer:

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