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andrew-mc [135]

3 years ago

15

Bryson is laying down sod in his yard to grow a new lawn .Each peice of sod is a 1-foot by 1-foot square .How many prices of sod

will Bryson need to cover his yard if his yard measures 30 feet by 14 feet

1 answer:

Marina86 [1]3 years ago

3 0

30 feet by 14 feet just means 30x14 which is equal to 420 square feet if each piece is 1x1 then he will need 420 pieces of sod

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Elina [12.6K]

Answer:

n ÷ 2

Step-by-step explanation:

if you insert a 12 for 'n', the corresponding value below would be 12÷2, or 6

this follows the pattern in the table

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2 years ago

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andrezito [222]

Answer:

X = 70 degrees

Step-by-step explanation:

The way to figure this out is by taking the angle of the 30 degrees and applying it to the opposite side of its self then just add it to the 80 degrees which will equal 110 and since a straight line has 180 degrees just subtract 180 by 110 and that will be the value of x because the lines are parallel and the line that goes through both lines will always have the same angle.

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2 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

l is length
w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle l = 10 \ meters$ <u />

<u /> $\displaystyle \frac{dl}{dt} = 4 \ m/day$ <u />

<u /> $\displaystyle w = 23 \ meters$ <u />

<u /> $\displaystyle \frac{dw}{dt} = 1 \ m/day$ <u />

<u />

<u>Step 2: Differentiate</u>

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

<u>Step 3: Solve</u>

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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3 years ago

(-1) + (-7) answer with work shown

lesya [120]

Answer is -8

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3 years ago

3(5z - 7) - 2 (9z - 11) = 4 (8z - 13) - 17

marysya [2.9K]

Answer z=2

See picture attached for the math

3 0

1 year ago