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3 years ago

I need help w/ these two questions you will get BRAINLIST

Mathematics

1 answer:

Leno4ka [110]3 years ago

8 0

Answer:

1a: f(-2) means substituting -2 for x

1b: 65

I don't know the second one

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Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

4 years ago

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Whoops solved it sorry

maksim [4K]

Mark brainiest ?!?!?!?!?!?!?

5 0

3 years ago

Find the value of x in the triangle shown below

tino4ka555 [31]

Answer:

Step-by-step explanation:

This is an isosceles triangle since two sides have length 10. The angles opposite the congruent sides are congruent. There is an angle measuring 116 deg, and two angles measuring x. The sum of the measures of the angles of a triangle is 180.

x + x + 116 = 180

2x + 116 = 180

2x = 64

x = 32

5 0

3 years ago

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Let A and B are n x n matrices from which A is invertible. Suppose AB is singular. What conclusion can be made about the inverti

Montano1993 [528]

Answer: Matrix B is non- invertible.

Step-by-step explanation:

A matrix is said to be be singular is its determinant is zero,

We know that if a matrix is singular then it is not invertible. (1)

Or if a matrix is invertible then it should be non-singular matrix. (2)

Given : A and B are n x n matrices from which A is invertible.

Then A must be non-singular matrix. ( from 2 )

If AB is singular.

Then either A is singular or B is singular but A is a non-singular matrix.

Then , matrix B should be a singular matrix. ( from 2 )

So Matrix B is non- invertible. ( from 1 )

7 0

3 years ago

Please help it’s fraction percentage

adelina 88 [10]

give me brainlyest first sorry i just dont have any

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6 0

3 years ago

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