<h2>Steps:</h2>
So for this, we will be doing a system of equations. Using the info from our question, our two equations are:
(let x = greater number and y = lesser number)

Now, for this I will be using the substitution method. Since we know that x = 4y - 1, substitute that into the second equation:

From here we can solve for y. Firstly, combine like terms:

Next, subtract 4y on both sides of the equation:

Next, multiply both sides by -1:

Now that we know the value of y, substitute it into either equation to solve for x:

<h2>Answer:</h2>
In short, <u>5 is the lesser number and 19 is the greater number.</u>
Answer:
x = 1
y = 4
Step-by-step explanation:
5x + 2y = 13
x + 2y = 9
Add both equations.
6x + 4y = 22
Solve for x.
6x = 22 - 4y
x = 22/6 - 4/6y
Put x as 22/6 - 4/6y in the second equation and solve for y.
22/6 - 4/6y + 2y = 9
-4/6y + 2y = 9 - 22/6
4/3y = 16/3
y = 16/3 × 3/4
y = 48/12
y = 4
Put y as 4 in the first equation and solve for x.
5x + 2(4) = 13
5x + 8 = 13
5x = 13 - 8
5x = 5
x = 5/5
x = 1
Answer:
gf is the one of the it turn on my exam and after I I don't think they are not (the answer is B)
Answer:
Number of cinammon = 12
Number of chocolate = 21
Step-by-step explanation:
Given that:
Cost of Cinnamon candle , c = $3.50
Cost of chocolate candle , d = $2.50
Total amount raised, T = $94.50
d = 2c - 3
Total amount = (cost of Cinnamon * number sold) + (cost of chocolate * number sold)
94.50 = (3.50 * c) + (2.50 * (2c-3))
94.50 = 3.50c + 5c - 7.5
94.50 = 8.50c - 7.5
94.50 + 7.5 = 8.50c
102 = 8.50c
c = 102 / 8.50
c = 12
d = 2c - 3
d = 2(12) - 3
d = 24 - 3
d = 21
Answer:
The volume of the cone is 128π mm³ ⇒ answer (C)
Step-by-step explanation:
* Lets study the cone
- Its base is a circle
- Its height the perpendicular distance from its vertex to
the center of the base
- The length of its slant height = √(h² + r²)
- The volume of the con is 1/3 the volume of the cylinder
∵ The volume of the cylinder = πr²h
∴ The volume of the cone = (1/3) πr²h
* In our problem:
- r = 4 mm
- h = 24 mm
∴ Its volume = (1/3) × π × (4)² × 24 = 128π mm³
* The volume of the cone is 128π mm³