Solve the system of equations by graphing. Check your solution. 5x+y=14 2x-y=7

Mathematics

1 answer:

Fudgin [204]4 years ago

6 0

ANSWER

(3,-1)

EXPLANATION

The given system of equations is :

5x+y=14

2x-y=7

For the first equation when x=0,

5(0)+y=14

y=14

The y-intercept is (0,14).

When y=0, 5x+0=14

$x = \frac{14}{5} = 2 .8$

The x-intercept is (2.8,0).

We plot the intercepts and draw a straight line through them to obtain the graph of 5x+y=14 as shown in the attachment.

We repeat the same process for the second equation 2x-y=7.

The intercepts are (0,-7) and (3.5,0)

The solution to the system is the point of intersection of the two straight lines.

The two straight lines intersected at

(3,-1)

Hence x=2, y=-1

You might be interested in

What are the zeros of the function f(x) = x^4 - x² - 2?

vaieri [72.5K]

Answer:

$x= i\\\\ x = -i \\\\x=\sqrt 2\\\\x = -\sqrt 2$

Step-by-step explanation:

$~~~~~~x^4 -x^2 -2=0\\\\\implies x^2 \cdot x^2-2x^2 +x^2 -2 = 0\\\\\implies x^2(x^2 -2) +(x^2 -2) =0\\\\\implies (x^2 +1)(x^2 -2) = 0\\\\ \implies x^2 +1=0~~~~~~~~\text{or}~~~~~~~~~x^2 -2 = 0\\\\ \implies x = \pm\sqrt{-1}~~~~~~~\text{or}~~~~~~~~~~ x = \pm\sqrt 2\\\\\implies x= \pm i~~~~~~~~~~~~~\text{or}~~~~~~~~~ x= \pm\sqrt 2$

7 0

2 years ago

Lexi said that two lines

omeli [17]

Answer:

Step-by-step explanation:

The easy way to make 2 perpendicular lines is let one be x = 3 and let y = 2.

The third line can be anything that has a minus sign in front of the x. See the graph below. The third line cannot be perpendicular to the other 2.

Sorry, the bottom of the graph got cut off. If you print out the graph and extend the vertical line and the slanted line, you will see how this works.

The three lines are