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Schach [20]
3 years ago
5

Jenny and Julie each drank a cup of hot chocolate after playing in the snow.Jenny put 6 more marshmallows in her cup than Julie.

Together Jenny and Julie had a total of 6 marshmallows.Write a system of equations to find how many marshmallows Jenny(x) and Julie (y) each have their hot chocolate.
Answer choices:
X-y=6 and x=y+6
X+y=12 and x=y-6
X+y=6 and x=y+6
X+y=12 and y=x+6
Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

A. X-y=6 and x=y+6 I'm pretty sure

Sidana [21]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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<span>reducible.

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4 0
3 years ago
Find the number of primes less than 190 using the principle of inclusion-exclusion.
Troyanec [42]

The number of primes less than 190 using the principle of inclusion-exclusion are 42

<h3>Principle of inclusion- exclusion</h3>

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

Learn more about prime numbers here:

brainly.com/question/874965

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8 0
2 years ago
What is the scale factor from the original design to the enlarged design?
bazaltina [42]
The answer is 2 due to the fact that 2 is even, and can be added more than once.
5 0
3 years ago
Read 2 more answers
There are 8 tennis players in a round robin tournament, which means each team will play every other team once. How many matches
Aliun [14]
<h3>Answer:  28</h3>

==========================================================

Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

----------------------------------

Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

----------------------------------

Method 3

Use the nCr combination formula with n = 8 and r = 2

n C r = \frac{n!}{r!(n-r)!}\\\\8 C 2 = \frac{8!}{2!*(8-2)!}\\\\8 C 2 = \frac{8!}{2!*6!}\\\\8 C 2 = \frac{8*7*6!}{2!*6!}\\\\ 8 C 2 = \frac{8*7}{2!}\\\\ 8 C 2 = \frac{8*7}{2*1}\\\\ 8 C 2 = \frac{56}{2}\\\\ 8 C 2 = 28\\\\

There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).

Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.

7 0
2 years ago
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