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4 years ago

What is the equation of the following line? (0,0) (2,-8)

Mathematics

2 answers:

Ivahew [28]4 years ago

6 0

Use the slope to do

(-8-0)/(2-0)

-8/2 = -4

The slope is -4

y = -4x

lakkis [162]4 years ago

6 0

Answer:

The required equation of the line is $y=-4x$

Step-by-step explanation:

Given : Points (0,0), (2,-8).

To find : What is the equation of the line ?

Solution :

Applying Two point slope form to find the equation,

$(y-y_1)=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Where, $(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(2,-8)$

Substitute in the formula,

$(y-0)=\frac{-8-0}{2-0}(x-0)$

$y=\frac{-8}{2}x$

$y=-4x$

Therefore, The required equation of the line is $y=-4x$

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Can this be simplified?

liraira [26]

No Nothing Further Can Be Done

6 0

3 years ago

Read 2 more answers

The measurement of an acute angle is (5w+8) solve for w

laiz [17]

Answer:

w < 82/5

Step-by-step explanation:

5w + 8 < 90

5w < 82

w < 82/5

6 0

3 years ago

To graduate this semester, you must pass Statistics 314; and you estimate that you have an 85% chance of passing. You need to pa

Nitella [24]

Answer:

Probability of graduating this semester is 0.7344

Step-by-step explanation:

Given the data in the question;

let A represent passing STAT-314

B represent passing at least in MATH-272 or MATH-444

M1 represent passing in MATH-272

M2 represent passing in MATH-444

C represent passing GERMAN-32

now

P( A ) = 0.85, P( C ) = 90, P( M1 ) = P( M2 ) = 0.8

P( B ) = P( pass at least one of either MATH-272 or MATH-444 ) = P( pass in MATH-272 but not MATH-444 ) + ( pass in MATH-444 but not in MATH 272) + P( pass both )

P( B ) = P( M1 ) × ( 1 - P( M2 ) ) + ( 1 - P( M1 ) ) × P( M2 ) + P( M1 ) × P( M2 )

we substitute

⇒ 0.8×0.2 + 0.2×0.8 + 0.8×0.8 = 0.16 + 0.16 + 0.64 = 0.96

∴ the probability of graduating this semester will be;

⇒ P( A ) × P( B ) × P( C )

we substitute

⇒ 0.85 × 0.96 × 90

⇒ 0.7344

Probability of graduating this semester is 0.7344

6 0

3 years ago

A rectangular garden has an area of 24 square meters. The width is 8 meters less than twice the length. Find the dimensions of t

OLEGan [10]

Answer:

Length: 6 m

Width: 4 m

Step-by-step explanation:

Area: 24 $m^{2}$

Width: 2L - 8 m

Length: ?

Formula: A = W * L

Replace the variables:

24 = (2L - 8) * L

24 = 2 $L^{2}$ - 8L

0 = 2 $L^{2}$ - 8L - 24

2 $L^{2}$ - 8L - 24 = 0

Solve; if you don't know how to solve it using this method, let me know. It's the expression $Ax^{2} +Bx+C$

1. $2 (\frac{(2L^2 - 8L - 24)}{2})$

2. $\frac{(2L)^2 - 8(2L) - 48}{2}$

3. $\frac{(2L - 12)(2L + 4)}{2}$

4. $2(\frac{(L - 6)(2L + 4)}{2})$

5. (L-6) (2L+4)

6. L-6 = 0 AND 2L+4 = 0

L - 6 =0

L = 6

---------------------------------

2L = -4

L = $\frac{-4}{2}$

L = -2

Since the length cannot be negative, the only real value is 6.

Area: 24 $m^{2}$

Width: 2L - 8 m

Length: 6 m

Calculate width:

W = 2L - 8

W = 2(6) - 8

W = 12 - 8

W = 4 m

3 0

3 years ago

Work out the point of intersection of the lines<br> 2x + 3y = 11 and 2y = 13 – 3x

borishaifa [10]

Answer:

x = 3.4

y = 1.4

Step-by-step explanation:

2x + 3y = 11

2y = 13 – 3x, then y = (13 - 3x)/2

substitute for y:

2x + 3((13 - 3x)/2) = 11

reduce:

2x + (39 - 9x)/2 = 11

reduce:

2x + 19.5 - 4.5x = 11

subtract 19.5 from both sides of the equation and combine for x:

-2.5x = -8.5

divide both sides by -2.5:

x = 3.4

y = (13 - 3(3.4))/2 = (13 - 10.2)2 = 1.4

3 0

3 years ago