Y=10. Hopefully this picture explains it
Y=-13×-10+4
y=130+4
y=134
y=-13×10+4
y=-130+4
y=-126
10=-13x+4
6=-13x
0.46~x
-10=-13x+4
-14=-13x
1.08~x
-6 and -8.
Set as x and x-2
Create an equation of 3(x) = (x-2)-10
Solve, x = -6.
So, x-2 = -8.
Answer:
8 potential winners ( 444, 446, 644, 464, 466, 646, 664, 666)
Step-by-step explanation:
To alter the odds the balls numbered 4 and 6 werent injected with liquid and hence they will float making it certain for their selection and determination as the winning digits. The potential of the winning numbers are (2)^3=8.
Since 4 and 6 ain't filled with liquid, they would be selected and determine the digits in the winning numbers in 8 ways ( 444, 446, 644, 464, 466, 646, 664, 666). The potential winning number is among them.
Note: Consider we need to find each type of coins he has.
Given:
Erin has quarters and nickels for a total of 16 coins.
The value of his coins is $2.60.
To find:
The number of each type of coins.
Solution:
Let x represent the number of quarters and y represent the number of nickels.
According to the question,
Total coins :
...(i)
Total value :
...(ii)
Multiply equation (i) by 0.25 and subtract the result from (ii).



Divide both sides by -0.20.

Put y=7 in (i).



Therefore, the number of quarters is 9 and number of nickels is 7.