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dmitriy555 [2]
4 years ago
10

if L, M, and N are collinear with M BETWEEN L and N, MN = 5, and LN = 18, then what is the length LM?

Mathematics
1 answer:
bulgar [2K]4 years ago
7 0

Answer:

LM = 13

Step-by-step explanation:

Given

MN = 5

LN = 18

Required

Find\ LM

Since, M is between LN, we have:

LN = LM + MN

Substitute values for MN and LN

18 = LM + 5

Make LM the subject

LM = 18 - 5

LM = 13

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Answer:

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Step-by-step explanation:

To solve this we are using the standard growth equation:

y=a(1+b)^x

Were

y is the final value after x years

a is the initial value

b is the growth factor (yearly rate of appreciation in our case) in decimal form

x is the time in years

We know from our problem that gold coin appreciated in value from $200.00 to $475.00 in 6 years, so y=475, a=200, and x=6.

Let's replace the values in our equation and solve for b:

y=a(1+b)^x

475=200(1+b)^6

\frac{475}{200} =(1+b)^6

2.375=(1+b)^6

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1+b=\sqrt[6]{2.375}

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Since our appreciation rate is in decimal form, we need to multiply it by 100% to express it as percentage:

0.16*100% = 16%

We can conclude that the yearly appreciation rate of our gold coin is approximately 16%

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divide top and bottom by 54
hope it helps</span>
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