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Morgarella [4.7K]

3 years ago

6

If you doubled the radius of a sphere, how would the surface area change?

2 answers:

noname [10]3 years ago

3 0

The area scale factor is the length scale factor squared. The length scale factor in this question is 2 (from the doubled radius) so the area scale factor is 2 squared, 4. This means that the surface area will be 4 times larger than it was originally.

Nuetrik [128]3 years ago

3 0

Answer:

The area will get quadrupled that is four times.

Step-by-step explanation:

Surface area of sphere, A = 4πr²

If you doubled the radius of a sphere how would the surface area change.

New radius = 2r

New surface area of sphere, A' = 4π x (2r)²=16πr² = 4A

So the area will get quadrupled that is four times.

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35 because you add 3 and 6 and that gives you 35x

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Because one of the negatives if before the fraction, it doesn't matter if the second negative is on the 13 or on the 12.

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4 0

3 years ago

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Age If you add Natalie's age and Fred's age, the result is 40. If you add Fred's age to 4 times

jolli1 [7]

Answer:

Fred is 28 yrs old. Nathalie is 12yrs old

Step-by-step explanation:

Let Nathalie's age be x

Let Fred's age be a

x+a=40 yrs•••••1

4x+a=76yrs•••••2

a=40-x

Substitute a for 40-x in equation (2)

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5 0

2 years ago

Evaluate the expression 8x when x=2.

Dmitry [639]

Answer:

16

Step-by-step explanation:

8x

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3 0

3 years ago

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What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

Rainbow [258]

Answer:

The base is: $3 \sqrt[3]{4}$

Step-by-step explanation:

Given

$f(x) = \frac{1}{4}(\sqrt[3]{108})^x$

Required

The base

Expand 108

$f(x) = \frac{1}{4}(\sqrt[3]{3^3 * 4})^x$

Rewrite the exponent as:

$f(x) = \frac{1}{4}(3^3 * 4)^\frac{1}{3}^x$

Expand

$f(x) = \frac{1}{4}(3^3^\frac{1}{3} * 4^\frac{1}{3})^x$

$f(x) = \frac{1}{4}(3 * 4^\frac{1}{3})^x$

Rewrite as:

$f(x) = \frac{1}{4}(3 \sqrt[3]{4})^x$

An exponential function has the following form:

$f(x)=ab^x$

Where

$b \to base$

By comparison:

$b =3 \sqrt[3]{4}$

So, the base is: $3 \sqrt[3]{4}$

4 0

3 years ago