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noname [10]
3 years ago
5

Which of the following is the graph of the quadratic function y = x2 - 4x +4?​

Mathematics
2 answers:
Airida [17]3 years ago
7 0

Answer:

B. Graph D

Step-by-step explanation:

Start with the vertex formula for each, <em>y</em><em> </em><em>=</em><em> </em><em>a</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>h</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>k</em><em>,</em><em> </em>where (<em>h</em><em>,</em><em> </em><em>k</em>) → (<em>2</em>, <em>0</em>) is the vertex, plus, -h gives you the OPPOSITE terms of what they really are, and k gives you the EXACT terms of what they really are. So, insert the vertex into the Vertex Equation FIRST, y = (x - 2)². We reason why there is no <em>k</em><em> </em>is because it is represented by 0. So, squaring this monomial will give us <em>x</em><em>²</em><em> </em><em>-</em><em> </em><em>4x</em><em> </em><em>+</em><em> </em><em>4</em><em>.</em><em> </em>Ta Da!

I am joyous to assist you anytime.

Pavlova-9 [17]3 years ago
7 0

Answer:

answer is B

Step-by-step explanation:

cause the other person answered it lol

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Step-by-step explanation:

You have to use logarithms.

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Answer:

Step-by-step explanation:

Altura = 11.312 pies

i) La escalera que descansa contra la pared formará un triángulo en ángulo recto.

ii) la escalera formará la hipotenusa del triángulo rectángulo dado por h = 12 pies.

iii) La base está dada por 4 pies.

iv) de la fórmula del triángulo en ángulo recto.

   base  = altura = \sqrt{hipotenusa^{2}\hspace{0.15cm}- \hspace{0.15cm} base^{2} }  = \sqrt{12^{2}\hspace{0.15cm} - \hspace{0.15cm}4^{2}  } = \sqrt{144\hspace{0.15cm} - \hspace{0.15cm}16} = \sqrt{128} = \hspace{0.15cm}8\sqrt{2} = 8\times1.414 = 11.312 pies

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Please help due tomorrow, multiple choice
anzhelika [568]

Answer:

Step-by-step explanation:

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3 years ago
What is the y-coordinate of the point that divides the
natima [27]

Answer:

y-coordinate = 0

Step-by-step explanation:

Consider the below diagram attached with this question.

Section formula:

If a point divides a line segment in m:n whose end points are (x_1,y_1) and (x_2,y_2), then the coordinates of that point are

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

From the below graph it is clear that the coordinates of end points are J(1,-10) and K(7,2). A point divides the line JK is 5:1.

Using section formula, the coordinates of that point are

(\frac{(5)(7)+(1)(1)}{5+1},\frac{(5)(2)+(1)(-10)}{5+1})

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(\frac{36}{6},\frac{0}{6})

(6,0)

Therefore, the y-coordinate of the point that divides the directed line segment from J to k into a ratio of 5:1 is 0.

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