Question

Determine the number of real solutions of -2x^2+5x-3=0

Answer 1

Answer:

Two distinct real solutions.

Step-by-step explanation:

Given the equation in the form $ax^2+bx+c=0$, you need to find the Discriminant with this formula:

$D=b^2-4ac$

For the equation $-2x^2+5x-3=0$ you can identify that:

$a=-2\\b=5\\c=-3$

Then, substituting these values into the formula, you get that the Discriminant is:

$D=5^2-4(-2)(-3)$

$D=1$

 Since $D>0$, then $-2x^2+5x-3=0$ has two distinct real solutions.