B. if two lines are perpendicular, then they intersect to form four right angles.
You reflect point A over the x-axis, double the distance from point a to the x-axis, then give the coordinates.
ex/ point A to the x-axis: 6, reflection: 12. coordinates (-6, 5)
I’m assuming you are talking about number four. If you look at the line it provides you, the slope is -.5 and the intercept is zero. So all you have to do is rewrite the equation but subtract four from the right side and it will be parallel.
X^2-6x+7=0
-b +/- sqrt b^2-4ac all over 2a
a=1 b= -6 and c=7
6+/- sqrt 36-4×1×7 all over 2×1
6+/- sqrt 8 all over 2
6+/- 2sqrt2 all over 2
reduce
3+/- sqrrt2
3 (-2)^2 -5 (3)+8
3 (4)-5 (3)+8
12-15+8
-3+8=5
Hope this helps :)
