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Alla [95]
3 years ago
9

Is x = 8 a solution to the equation 16 - x/4 = 12?

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0
<span>x/8+12 = 16 // - 16

x/8-16+12 = 0

1/8*x-4 = 0 // + 4

1/8*x = 4 // : 1/8

x = 4/1/8

x = 32

x = 32
</span>
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Find the measure of &lt;2.
iVinArrow [24]
Should be 30 as well
5 0
2 years ago
Read 2 more answers
∠A and \angle B∠B are supplementary angles. If m\angle A=(x-16)^{\circ}∠A=(x−16) ∘ and m\angle B=(3x+28)^{\circ}∠B=(3x+28) ∘ , t
GalinKa [24]

Answer:

  ∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

  ∠A +∠B = 180°

  (x -16)° +(3x +28)° = 180°

  4x° + 12° = 180°

  x° +3° = 45°

  x° = 42°

  ∠A = (x -16)° = 42° -16°

  ∠A = 26°

3 0
3 years ago
Write the name of the period that has the digits 486
kogti [31]
1.       <span>The name of period that has 486 in the given number which is 751 486  is hundreds.
period is considered to a group of places of the digits, like the given number 486 is the group of hundred because the highest number it contains is 400.
=> 400 + 80 + 6
=> 4 hundreds + 8 tens + 6 ones
=> 486
while 751 is the period of hundred thousands.
=> 700 000 + 50 000 + 1 000
=> 751 000

</span>
8 0
3 years ago
2.
laiz [17]

Answer:

B) 0.02

Step-by-step explanation:

<u>Use the Binomial Theorem</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=4)=\binom{30}{4}(0.30)^4(1-0.30)^{30-4}\\\\P(X=4)=\frac{30!}{4!(30-4)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30!}{4!(26)!}(0.30)^4(0.70)^{26}\\ \\P(X=4)=\frac{30*29*28*27}{4*3*2*1}(0.30)^4(0.70)^{26}\\ \\P(X=4)=27405(0.30)^4(0.70)^{26}\\\\P(X=4)\approx0.0208

We have the probability of success, p=0.30, and the probability of failure, q=1-0.30=0.70. The binomial coefficient, \binom{n}{k}, represents the amount of possible combinations that k items can be chosen out of n items, with its respective formula \frac{n!}{k!(n-k)!}.

Hence, the best choice for the probability that 4 students chosen at random from the class of 30 that want the next test to be on Monday will be option B, 0.02

7 0
2 years ago
Which value is equivalent to ( 7 • 5 • 2 over 7 • 3) ^2 • ( 5^0 over 2^-3) ^3 • 2^-9
ser-zykov [4K]
100 / 9

They both equal 11.11
(70/21)^2 * 8^3 * (1/2^9)
3 0
3 years ago
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