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Anarel [89]
3 years ago
6

Help me please The ordered pair for 3x + 4y > 17 (-2, -5) (2, 4) (0, -2)

Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

2 and 4

Step-by-step explanation:

2 x 3 = 6

+

4 x 4 = 16

__________

22

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Solve this linear equation for p.
Vinvika [58]

Answer:

P = 11.2

Step-by-step explanation

6 0
2 years ago
Read 2 more answers
6. If b&gt;6, then 3b + 3 could be<br> A. 18<br> B. 19<br> C. 20<br> D. 21<br> E. 22
Gala2k [10]

Answer:

E. 22

Step-by-step explanation:

Hello!

We know that b>6, and we are asked to find the possible values for 3b + 3.

Let's directly substitute 6 for b:

  • 3(6) + 3
  • 18 = 3
  • 21

Now, because b is greater than 6, and not equal to 6, any value greater than 21 will work.

The correct option is E. 22.

7 0
2 years ago
I need the answer for part b​
Softa [21]

Answer:

4/4

Step-by-step explanation:

1/4 plus 1/4 plus 2/4 is 4/4

4 0
2 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
6 * ( 12 - 7.5 ) - 7
Paladinen [302]

Answer: 20

Explanation: Alright, so basically you’re going to want to use PEMDAS (Parenthesis, Exponents, Multiplication/ Division, Addition/ Subtraction)

* just means multiply.. sooo the problem looks like this:

6x(12-7.5)-7

We’ll start at the parentheses :)

So (12-7.5) = 4.5

Now our problem looks like: 6x(4.5)-7

Following PEMDAS, the next thing to come up is multiplication! So we’re going to multiply 6 by 4.5 ...

6x4.5=27

After this our problem looks like: 27-7

So now it’s just simple math...

27-7= 20

5 0
3 years ago
Read 2 more answers
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