The foci of the hyperbola with equation 5y^2-4x^2=20 will be given as follows:
divide each term by 20
(5y^2)/20-(4x^2)/20=20/20
simplifying gives us:
y^2/4-x^2/5=1
This follows the standard form of the hyperbola
(y-k)²/a²-(x-h)²/b²=1
thus
a=2, b=√5 , k=0, h=0
Next we find c, the distance from the center to a focus.
√(a²+b²)
=√(2²+(√5)²)
=√(4+5)
=√9
=3
the focus of the hyperbola is found using formula:
(h.h+k)
substituting our values we get:
(0,3)
The second focus of the hyperbola can be found by subtracting c from k
(h,k-c)
substituting our values we obtain:
(0,-3)

Thus we have two foci
(0,3) and (0,-3)

5 0

3 years ago

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Order the numbers from least to greatest -3/4, -4/15, -2/5

barxatty [35]

Answer:

-3/4, -2/5, -4/15

Step-by-step explanation:

using calculator, -3/4 = -0.75, -4/15 = -0.266666..., -2/5 = -0.40

imagine that -0.75, -0.26... and -0.40 are temperatures

the coolest temperature is -0.75, the warmest one is -0.26...

so the least number is -0.75, greater -0.40 and the greatest -0.26...