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Assoli18 [71]
2 years ago
6

The perimeter of a shape is 25.71 cm calculate the value of the radius X takes pie to be 3.142

Mathematics
1 answer:
Mariulka [41]2 years ago
3 0

Answer:

5 cm

Step-by-step explanation:

Given a semicircle with perimeter 25.71 cm, we are required to find the radius of the circle.

Circumference of a Semicircle

=Length of the Circular part+Length of the diameter

=\pi r+2r

If \: \pi=3.142, C=25.71\\Then:\\25.71=3.142r+2r\\r(3.142+2)=25.71\\5.142r=25.71\\r=25.71 \div5.142\\r=5cm

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Sophia pays a
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Answer:

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Step-by-step explanation:

19.99 + 0.99x

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3 years ago
What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

Hence The given statement is False.

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Now On solving we get;

\frac{18}{32}=0.5625

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So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

\frac{28}{23}=1.2

So we can see that 1.33 > 1.2

Hence The given statement is False.

4.  \frac{29}{35}

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\frac{29}{35}= 0.82

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So we can see that 0.82 > 0.66

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7 0
3 years ago
Determine the length of the longest metal rod which could be stored in a rectangle box 20 cm by 50 cm by 30 cm.
navik [9.2K]

Answer:

61.64 cm

Step-by-step explanation:

The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:

\therefore \: length \: of \:metal \: rod  \\  =  \sqrt{ {l}^{2} +  {b}^{2}   +  {h}^{2} }  \\  =  \sqrt{ {20}^{2} +  {50}^{2}  +  {30}^{2}  }  \\  =  \sqrt{400 + 2500 + 900}  \\  =  \sqrt{3800}  \\  = 61.64414 \\  = 61.64 \: cm

5 0
3 years ago
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Ipatiy [6.2K]

Answer:

The y-intercept would be 7

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3 years ago
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