Question

The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 N. The canister initially has a velocity of 2.3 m/s in the positive x direction, and some time later has a velocity of 6.4 m/s in the positive y direction. How much work is done on the canister by the 3.0 N force during this time?

Answer 1

Answer:44.58 J

Explanation:

mass of block $\left ( m\right )=2.5 kg$

Force magnitude=3 N

Initial velocity =$2.3\hat{i} m/s$

Final velocity=$6.4\hat{j} m/s$

Initial Kinetic Energy=$\frac{1}{2}mv^2$

=$\frac{1}{2}\times 2.5\times 2.3^2=6.612 J$

Final Kinetic Energy=$\frac{1}{2}mv^2$

=$\frac{1}{2}\times 2.5\times 6.4^2=51.2 J$

Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J