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nika2105 [10]
3 years ago
6

The only force acting on a 2.5 kg canister that is moving in an xy plane has a magnitude of 3.0 N. The canister initially has a

velocity of 2.3 m/s in the positive x direction, and some time later has a velocity of 6.4 m/s in the positive y direction. How much work is done on the canister by the 3.0 N force during this time?
Physics
1 answer:
Effectus [21]3 years ago
4 0

Answer:44.58 J

Explanation:

mass of block \left ( m\right )=2.5 kg

Force magnitude=3 N

Initial velocity =2.3\hat{i} m/s

Final velocity=6.4\hat{j} m/s

Initial Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.5\times 2.3^2=6.612 J

Final Kinetic Energy=\frac{1}{2}mv^2

=\frac{1}{2}\times 2.5\times 6.4^2=51.2 J

Work Done =Final -Initial Kinetic energy=51.2-6.612=44.58 J

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