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2 years ago

Why can't we say a measurement tool is accurate?

1 answer:

7 0

There are various reasons why a measurement tool cannot be accurate. One of them is thermal contraction and expansion varies according to seasons.

<h3>What are Accuracy and Precision?</h3>

There are two ways to assess observational error: accuracy and precision. Precision measures how closely two measurements are to one another, whereas accuracy measures how close a group of measurements is to its actual value. In other words, precision is a measure of statistical variability and a description of random errors.

We can say that a tool can be precise, but it cannot be accurate. There are various reasons behind that, some of them are :

It may not be calibrated properly. If there are no reliable standards to use for calibration, this may occur.
Perhaps it strayed. This is why electronic scales include a tare function—they are terrible in this area.
Perhaps the measurements are not linear. Our calipers might have been quite precise at the 2-inch standard, where they were calibrated, but inaccurate at other dimensions.
Temperature is one environmental component that the instrument might be sensitive to. These effects might be compensated for, but the compensation might not be ideal. This issue affects both dissolved solids meters and picometers.

These are some of the reasons due to which measurement tool cannot be accurate.

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A ball is thrown with velocity of 10 m/s upwards. If the ball is caught 1 m above its initial position, what is the speed of the

White raven [17]

Answer:

v = 8.96 m/s

Explanation:

Initial speed of the ball, u = 10 m/s

It caught 1 meter above its initial position.

Acceleration due to gravity, $g=-9.8\ m/s^2$

We need to find the final speed of the ball when it is caught. Let is equal to v. To find the value of v, use third equation of motion as :

$v^2-u^2=2as$

$v^2=2as+u^2$

$v^2=2(-9.8)\times 1+(10)^2$

v = 8.96 m/s

So, the speed of the ball when it is caught is 8.96 m/s. Hence, this is the required solution.

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3 years ago

Read 2 more answers

What is a common misconception/mistake made when calculating the final velocity for a falling object

vaieri [72.5K]

Answer:

Velocity (v) can be calculated via v = gt, where g represents the acceleration due to gravity and t represents time in free fall. Furthermore, the distance traveled by a falling object (d) is calculated via d = 0.5gt^2.

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3 years ago

Consult Multiple-Concept Example 9 to explore a model for solving this problem. A person pushes on a 63-kg refrigerator with a h

miskamm [114]

Answer:

a ) 270 N

b )413.65 N

Explanation:

weight of the refrigerator = reaction force ( R )

= mg

= 63 x 9.8

R = 617.4 N

Maximum friction possible

= coefficient of friction x R

= .67 X 617.4

= 413.65 N

When force 270 N is applied , due to friction, the body does not move .

The friction force adjusts itself to the external applied force to prevent the body to budge.

Hence the friction force acting in this situation = 270 N

b ) The maximum friction possible is 413.65 . If we apply a force equal to or exceeding 413.65 N , body will move. Hence 413.65 N is the answer.

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3 years ago

A spring stores 10. joules of elastic potential

Mekhanik [1.2K]

The answer would be . Since we are looking for the spring constant you would need to use the formula
$PEs = \frac{1}{2} k {x}^{2}$
. Then you'd substitute, for PEs and x.
$10j=1/2k(.20m^2).$
Then solve. k=500n/m

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4 years ago

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Four cubes of the same volume are made of different materials: lead (density 11,300 kg/m3), aluminum (density 2700 kg/m3), wood

xz_007 [3.2K]

Answer:

1. Lead

2. Aluminum

3. Wood

4. Styrofoam

Explanation:

Specific gravity is a quantity that tells me how much an object is submerged on a fluid relating the densities:

$S.G=\frac{\rho_{object}}{\rho_{fluid}}$

Because all the cubes are placed on water, the density of the fluid is the same for all the cubes and S.G. is directly proportional to the density of the cube material. So, for greater density greater S.G.

The Archimedes principle states that the buoyant force is equal to the weight of water displaced, that is:

$\overrightarrow{B}=-\overrightarrow{W_{displaced}}$

So, the cube that submerges more is the cube that mor displace water and is the cube that has more buoyant force on it. In other words, the cubes with higher S.G. have more buoyant force, and because S.G is proportional to cube density, the cubes with more buoyant force have more density.

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3 years ago