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3 years ago

14

What happens to a shopping cart if you get it rolling and then release it?

1 answer:

Anit [1.1K]3 years ago

7 0

Answer:

It will slowly come to a stop as long as it is moving on a flat surface

Explanation:

If the cart is moving on a flat surface, it will slowly come to a stop due to the friction forces acting on its wheels.

If the cart is on an inclined surface, it may gain acceleration enough to overcome any friction force, and thus continue with an accelerated motion.

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Two particles with charges +6e and -6e are initially very far apart (effectively an infinite distance apart). They are then fixe

JulijaS [17]

Answer:

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}\ J.$

Explanation:

Given charges are:

$\rm q_1 = +6e.\\q_2 = -6e.$

The electric potential energy of a charge due to the electric field of another charge is given by

$\rm EPE=\dfrac{kq_1q_2}{r}.$

where,

k = Coulomb's constant, having value = $\rm 9\times 10^9\ Nm^2/C^2.$
r = distance between the charges.

When the charges are infinite distance apart, $\rm r = \infty$ ,

$\rm EPE_{initial} = \dfrac{kq_1q_2}{r}=0\ J.$

When the charges are $\rm 5.61\times 10^{-12}\ m$ apart, $\rm r=5.61\times 10^{-12}\ m$ ,

$\rm EPE_{final}=\dfrac{kq_1q_2}{r}\\=\dfrac{(9\times 10^9)\times (+6e)\times (-6e)}{5.61\times 10^{-12}}\\=-5.775\ e^2\times 10^{22}.$

Here, e is the charge on one electron, such that, $\rm e = -1.6\times 10^{-19}\ C$ .

Therefore,

$\rm EPE_{final}=-5.775\times (-1.6\times 10^{-19})^2\times 10^{22} = -1.478\times 10^{-15}\ J.$

Thus,

$\rm EPE_{final}-EPE_{initial}=-1.478\times 10^{-15}-0=-1.478\times 10^{-15}\ J.$

4 0

3 years ago

The first hill of a roller coaster is 42 meters high. The top of the second hill of the one

Marta_Voda [28]

Answer:

Part a)

Speed of the roller coaster is

$v = 13.3 m/s$

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

Explanation:

As we know that there is no friction on the path

So here we can use mechanical energy conservation law

so we will have

Part a)

$U_i + K_i = U_f + K_f$

$mgh + 0 = \frac{1}{2}mv^2 + mgH$

$34500(9.81)(42) = \frac{1}{2}(34500)v^2 + 34500(9.81)(33)$

$v = 13.3 m/s$

Part b)

Since it is moving with non zero speed at some height above the ground

So we will have

Kinetic energy + Potential energy Both

7 0

4 years ago

Read 2 more answers

Which of the following is not a function of protein?

Bess [88]

Answer: I Believe The Answer Is A. Insulating The Body

5 0

3 years ago

Read 2 more answers

You are building a race car your goal is to have a car that can go from 0 miles per hour to 80 miles per hour in 2 seconds you a

stich3 [128]

Whats the question? I ont understand

8 0

4 years ago

A block is pushed across a rough horizontal surface from point A to point B by a force P. The magnitude of the force of friction

DochEvi [55]

Answer:

The workdone by P is $W_p=2.2J$

Explanation:

Generally workdone is mathematically represented as

$W = F *d$

Where F is the force and d is the distance

The total workdone = (Workdone by Force P + Workdone by frictional force )

The difference in kinetic energy

$\Delta KE = KE_2 - KE_1$

Substituting 5.6 J for $KE_1$ and 4.0 J for $KE_2$

$\Delta KE = 5.6 - 4$

$= 1.6J$

This change in kinetic energy of the block = The total kinetic energy

The workdone by the frictional force is

$W_F = -F_f * d$

the negative sign shown that the force is moving in the opposite direction

substituting 1.2 N for $F_f$ and 0.5 m for d

$W_F = -1.2*0.5$

$=-0.6J$

Making Workdone by Force P the subject in the above equation we

Workdone by Force P ( $W_P$ ) = The total workdone( $W_T$ ) - $W_F$

Substitution values

$W_p = 1.6 -(-0.6)$

$W_p=2.2J$

4 0

3 years ago