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earnstyle [38]
3 years ago
14

Rewrite the expression in terms of sine and cosine, and simplify as much as possible. (sec w(1+ csc^2 w))/(csc^2 w)​

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0

Answer:

(sin^2 w + 1) / cos w.

Step-by-step explanation:

Note: sec w = 1 / cos w and csc w = 1/ sin w.

So we have:

(sec w(1 + csc^2 w)) / (csc^2 w)​

= 1/cos w (  1 + 1/ sin^2 w)  /   (1 / sin^2 w)

= ( 1/ cos w + 1 / sin^2 w cos w) * sin^2 w

=  sin^2 w/ cos w + sin^2 w / (sin^2 w cos w)

= sin^2 w / cos w + 1 /  cos w

=  (sin^2 w + 1) / cos w.

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Could I have some help on my patterns assignment​
nydimaria [60]

Answer:

1. 13, 18, 23, 28, 33, 38, 43, 48, 53

<em>Conjecture:</em> Each term is 5 more than the previous term.

2. 512, 256, 128, 64, 32, 16, 8, 4, 2

<em>Conjecture:</em> Each term is half of the previous term.

3. 1, 8, 27, 64, 125, 216, 343, 512, 729

<em>Conjecture:</em> Each term is a cube. To find the nth term, cube n.

4. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

<em>Conjecture:</em> Each term is the next consecutive prime number.

5. <u><em>Correct as is</em></u>

6. 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89

<em>Conjecture:</em> Each term is the sum of the 2 previous numbers.

Step-by-step explanation:

1.

Given: 13, 18, 23, 28

<em>We add 5 to each number</em>

13 + 5 = 18

18 + 5 = 23

23 + 5 = 28

28 + 5 = 33

33 + 5 = 38

38 + 5 = 43

43 + 5 = 48

48 + 5 = 53

2.

Given : 512, 256, 128, 64

<em>Divide each number by 2</em>

512 ÷ 2 =256

256 ÷ 2 = 128

128 ÷ 2 = 64

64 ÷ 2 = 32

32 ÷ 2 = 16

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

3.

Given: 1, 8, 27, 64

<em>We have to cube n:</em>

<u><em>n³ = consecutive number cubed</em></u>

<u><em></em></u>

1³ = 1 or 1 × 1 × 1

2³ = 8 or 2 × 2 × 2

3³ = 27 or 3 × 3 × 3

4³ = 64 or 4 × 4 × 4

5³ = 125 or 5 × 5 × 5

6³ = 216 or 6 × 6 × 6

7³ = 343 or 7 × 7 × 7

8³ = 512 or 8 × 8 × 8

9³ = 729 or 9 × 9 × 9

4.

Consecutive prime number: <u><em>Consecutive prime numbers are those that have no gaps or prime numbers between them.</em></u>

Look at the picture in the link:

6.

Given: 1, 1, 2, 3, 5, 8

<em>We must add the two previous numbers to get the next term:</em>

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

13 + 21 = 34

21 = 34 = 55

34 + 55 = 89

8 0
1 year ago
2 ( x-4 ) = 5/6 ( x+6 ) -6
givi [52]
Hopes this helps:

Answer: x = 6
3 0
3 years ago
Aaron wants to mulch his garden. His garden is x^2+18x+81 ft^2 One bag of mulch covers x^2-81 ft^2 . Divide the expressions and
blsea [12.9K]

Answer:

Step-by-step explanation:

Given

Garden: x^2+18x+81

One Bag: x^2 - 81

Requires

Determine the number of bags to cover the whole garden

This is calculated as thus;

Bags = \frac{x^2+18x+81}{x^2 - 81}

Expand the numerator

Bags = \frac{x^2+9x+9x+81}{x^2 - 81}

Bags = \frac{x(x+9)+9(x+9)}{x^2 - 81}

Bags = \frac{(x+9)(x+9)}{x^2 - 81}

Express 81 as 9²

Bags = \frac{(x+9)(x+9)}{x^2 - 9\²}

Evaluate as difference of two squares

Bags = \frac{(x+9)(x+9)}{(x - 9)(x+9)}

Bags = \frac{(x+9)}{(x - 9)}

Hence, the number of bags is Bags = \frac{(x+9)}{(x - 9)}

3 0
3 years ago
Kent multiplies both sides of the equation below by an expression. k+12/k=8 Then he moves all the terms to one side of the equal
BartSMP [9]
<span>k+12/k=8
Multiply k to remove the k in one side
</span><span>(k+12/k=8) (k)
</span>Therefore, 
k^2+12k-8k=0

Thus,
The equations he must solved now is k^2-8+12=0
3 0
3 years ago
Read 2 more answers
Solve elimination method 3x+4y=0 and x - 2y =-5​
Alla [95]

Answer:

x=−2 and y=3/2

Step-by-step explanation:

see picture

5 0
2 years ago
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