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2 years ago

Write the slope-intercept form of the equation of each line given the slope and y-intercept.

Mathematics

1 answer:

olya-2409 [2.1K]2 years ago

4 0

Answer:

Y = -10X - 5

Step-by-step explanation:

Y = mX + b

m - slope

b - y - intercept.

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Find the regression line associated with the set of points. (Round all coefficients to four decimal places.) HINT (See Example 2

horrorfan [7]

The equation of the regression line is : Ŷ = 0.8571+0.8878X

Given the set of points :

(1, 2), (4,4), (9,9)

X axis : ___ Y axis

1 ___________2

1 ___________2 4 __________ 4

1 ___________2 4 __________ 4 9 __________ 9

The regression line associated could be obtained using technology such as excel, linear regression solvers or a graphing calculator.

Using technology :

Input the values of X and Y into their appropriate column and plot :

The regression equation obtained is :

Ŷ = 0.8571 + 0.8878X

Where :

Ŷ = predicted value of Y(dependent variable)

X = Independent variable

Slope = 0.8878

Intercept = 0.8571

The regression plot is attached below

Learn more : brainly.com/question/18405415?referrer=searchResults

7 0

2 years ago

The square of a number plus the original number is 22 what could the number be?

arlik [135]

Answer:

x²+22

Step-by-step explanation:

let the number= X

x²+22

7 0

2 years ago

Read 2 more answers

Help please its math triangles..

Fudgin [204]

Answer:

Step-by-step explanation:

Add the top and bottom bases, divide by 2, multiply by height.

4 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$