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belka [17]
3 years ago
11

A student observes 5,000 RFUs in a 200μl aliquot from a G3-500 ml culture. How many total RFUs will be present in a G3-15ml samp

le? During rGFP purification in lab#4, assume they recover 80% of the fluorescing protein. What would be the maximum total number of RFUs that they collected in the purification procedure? Show your calculations for full credit.
Biology
1 answer:
natka813 [3]3 years ago
5 0

Answer:

The maximum no. of RFUs collected in the purification procedure = 3.05 \times 10^5 RFUs

Explanation:

No. of RFUs in a 200 ul (0.2ml) aliquot = 5000 RFUs

So, No. of RFUs in G3-500 ml culture = 5000 \times \frac{500 ml}{0.2 ml} RFUs

                                                               = 5000 \times 2500 RFUs  

                                                                = 1.25 \times 10^7 RFUs

Similarly, No. of RFUs in a G3-15ml sample = 5000 \times \frac{15 ml}{0.2 ml} RFUs

                                                                          = 5000 \times 75 RFUs

                                                                          = 3.75 \times 10^5 RFUs

The maximum no. of RFUs collected in the purification procedure

= 3.75 \times 10^5 \times 80% RFUs

= 3.75 \times 10^5 \times 0.80 RFUs

= 3.05 \times 10^5 RFUs

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