Question

A certain liquid leaks out of a container at the rate of k liters for every x hours. if the liquid costs $6 per liter, what is the cost, in dollars, of the amount of the liquid that will leak out in y hours?

Answer 1

If k liters of liquid leak out every x hours, we can compute the amount of liters that leak out every hour:

$x \text{ hours} = k \text{ liters} \implies 1 \text{ hour} = \dfrac{x \text{ hours}}{x} = \dfrac{k}{x} \text{ liters}$

So, with each passing hour we lose $\frac{k}{x}$ liters. So, in $y$ hours we lose

$y \times \dfrac{k}{x} = \dfrac{ky}{x}$ liters.

Each of this liters costs 6$, so we lose a total of

$6 \times \dfrac{ky}{x} = \dfrac{6ky}{x}$ dollars.