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tatyana61 [14]
3 years ago
8

What is a circumference?

Mathematics
2 answers:
Fantom [35]3 years ago
7 0
The enclosing boundary of a curved geometric figure, especially a circle.
VMariaS [17]3 years ago
3 0

Answer:

The circumference is the enclosing boundary of a circle.

Step-by-step explanation:

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PLEASE HELP FAST!! ILL MARK AS BRAINLIEST!! Graphing is the best choice when solving for the following system:
Sedaia [141]
False. You can find the solution more quickly by solving the system algebraically.

-4x + 2y = 18

Since y=-3x+4,
-4x + 2(-3x+4) = 18
-4x - 6x + 8 = 18
-10x = 10
x = -1
y = -3x+4 = 7
8 0
3 years ago
Can someone help me out on this please having trouble on both and show work please !!
inysia [295]

The difference of the expression is as follows:

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5) = - 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4) = x - 19

<h3>How to find the difference of the expression?</h3>

The difference of the expression can be found when we combine the like terms.

Therefore,

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)

6y⁴ + 3y² - 7  - 12y⁴ + y² - 5

6y⁴ - 12y⁴ + 3y² + y² - 7 - 5

- 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4)

3x - 15 - 2x - 4

3x - 2x - 15 - 4

x - 19

learn more on expression here: brainly.com/question/14294918

#SPJ1

5 0
2 years ago
Is an arithmetic sequence a function?
Sphinxa [80]
Yes it is a linear function
3 0
3 years ago
480 is what percent greater than 160
MrMuchimi
160 is 100% of 160, 480 is 4 times that. So 400%
7 0
3 years ago
Read 2 more answers
How many solutions does the system have? \begin{cases} 5y =15x-40 \\\\ y = 3x-8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ 5y=15x−40 y=3x−8 ​ C
Ksenya-84 [330]

Answer:

(C) Infinitely many solutions

Step-by-step explanation:

Converting the lines into the from ax+by+c=0

5y=15x-40\\\Rightarrow 15x-5y-40=0

y=3x-8\\\Rightarrow 3x-y-8=0

\dfrac{a_1}{a_2}=\dfrac{15}{3}=5

\dfrac{b_1}{b_2}=\dfrac{-5}{-1}=5

\dfrac{c_1}{c_2}=\dfrac{-40}{-8}=5

So, \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}.

Hence, these lines have infinitely many solutions.

3 0
3 years ago
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