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3 years ago

Determine whether each of the following points is a solution to the given system. Justify your answer.

Mathematics

1 answer:

marissa [1.9K]3 years ago

6 0

Answer:

need more details

Step-by-step explanation:

what system

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Write the slope-intercept form of the equation of each line given the slope and y-intercept

amid [387]

The slope-intercept form of the equation for a line is ...
y = (Slope)x + (y-intercept)

Put the given information in the appropriate spot in the equation. Simplify as required.
y = (-1/3)x + 0
can be simplified to

y = (-1/3)x

6 0

3 years ago

Name two special right triangles by their angle measures.

Mandarinka [93]

Answer:

right angle?

Step-by-step explanation:

4 0

3 years ago

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Noah was assigned to make 64 cookies for the bake sale. He made 25% MORE than that. How many cookies did Noah make? Explain how

bazaltina [42]

Answer:

8 cookies were left after the bake sale. 72 were sold.

Step-by-step explanation:

64*1.25= 80

80*.9= 72

125% of 64 is equal to 80.

90% of 80 is equal to 72.

The number left was 10% of the number he made. The number he made was 125% of 64, so the number left was 8

10% × 125% × 64 = 0.125 × 64 = 8

thats all i could really come up with at the top of my head

6 0

3 years ago

Evaluate 5x10 -6²+5<br> A:9<br> B:19<br> C:43<br> D:85

lord [1]

The answer is your second number
B : 19

6 0

3 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

3 years ago