why does it take 3 copies of 1/6 to show the same amount as 1 copy of 1/2? explain your answer in words and pictures.
1 answer:
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Answer:
a)
b)
c)
Step-by-step explanation:
For total cost function , average cost is given by
i.e., total cost divided by number of units produced.
Marginal average cost function refers to derivative of the average cost function i.e.,
Given:
Average cost =
a)
At x = 50 units,
b)
Average cost =
c)
Marginal average cost:
Differentiate average cost with respect to
Take
using quotient rule,
Therefore,
Answer:
She purchased the item at a price of Rs 1,406.
Step-by-step explanation:
5% of discount:
This means that she paid 100% - 5% = 95% = 0.95 of the original price of x, that is, 0.95x, and 0.05x was the discount.
Original price:
She got the discount amount of Rs 74.
74 is 5% of the original price, that is:
What price she purchased:
74 subtracted from the original price, that is, x - 74. So 1480 - 74 = 1406.
She purchased the item at a price of Rs 1,406.
Answer:
46.67% probability that they flew with airline B.
Step-by-step explanation:
We have these following probabilities:
A 40% probability that a traveler chooses airline A.
A 35% probability that a traveled chooses airline B.
A 25% probability that a traveler chooses airline C.
If a passenger chooses airline A, a 10% probability that he arrives late.
If a passenger chooses airline B, a 15% probability that he arrives late.
If a passenger chooses airline C, a 8% probability that he arrives late.
If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?
This can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
So
What is the probability that the traveler flew with airline B, given that he was late?
P(B) is the probability that he flew with airline B.
So
P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.
P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).
So
Probability
46.67% probability that they flew with airline B.