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lana66690 [7]
3 years ago
15

How many pieces of string, each 1/5 m long, can be cut from a string 3 m long?

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0
15 pieces of string.
Mandarinka [93]3 years ago
3 0

Answer:

15 pieces

Step-by-step explanation:

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When One Route and their support act, Cinnamon Bunnies, played, £54,000 was split at a ratio of 1:3:8 between the arena, Cinammo
dimaraw [331]

The ratio is split as arena first, Cinnamon Bunnies second and One Route third.

Add the ratios together: 1 + 3 +8 = 12

Divide the total money by 12, then multiply that by the share One Route gets (8)

54,000 / 12 = 4,500

4,500 x 8 = 36,000

One Route get £36,000

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3 years ago
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Reggie was looking at a map of the school the scale shows that 1 inch equals 150 ft if the distance between his classroom in the
topjm [15]

Answer:

the actual distance is 1800 ft.

Step-by-step explanation:

Proportion states that the two fractions or ratios are equal.

Let x be the actual distance.

As per the statement:

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⇒1 inch = 150 ft.

if the distance between his classroom in the cafeteria measures 12 in on the map.

by definition of proportions we have;

\frac{1}{150} = \frac{12}{x}

By cross multiply we have;

x = 12 \cdot 150 = 1,800 ft

Therefore, the actual distance is 1800 ft.

4 0
4 years ago
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A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.
makvit [3.9K]
<h3>Answer: 7366.96 dollars</h3>

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Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

-------

Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

12000 = P(1.05)^(10)

12000 = P(1.62889462677744)

12000 = 1.62889462677744P

1.62889462677744P = 12000

P = 12000/1.62889462677744

P = 7366.95904248911

P = 7366.96

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What is ten million times three thousand
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