If they're different sizes and densities, you are able to separate the substances.
The product of this reaction is a halohydrin as shown here.
<h3>What are the products?</h3>
We have a reaction that first involves the formation an alkene as the bases are used on the first substrate. The alkene that is thus created is now able to react with the bromine in water.
The first step of the reaction is where the multiple bond is created and this multiple bond is what can now go on to participate in a chemical reaction in the next step of the process of reaction as shown in the image.
Bromine in water is also hat we call bromine water. This bromine water is able to add across a double bond and when that happen we will have a saturated compound. This could also be regarded as halohydrin reaction.
Recall that the first step of the reaction of the alkene with bromine is the formation of a dibromide via the brominium intermediate. This is now followed by reaction with water to form the halohydrin product.
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Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
Answer:
Alchemy is based on mystic view of reality whereas chemistry is based on experiments, observations and facts.