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zhenek [66]
3 years ago
15

1.0g of a protein is dissolved in 100 ml of distilled water. The resulting solution has an osmotic pressure of .001 atm. What is

the molecular weight of the protein? Use r = .0821 l atm-1 mol-1.
Chemistry
1 answer:
Svetlanka [38]3 years ago
7 0

The osmotic pressure π, is related to concentration i.e. molarity (M) through the following equation:

π = MRT ------(1)

where R = gas constant = 0.0821 L atm/mol-K

T = temperature (let us assume 25 C = 25 + 273 = 298 K)

M = π/RT = 0.001/0.0821 * 298 = 4.09 * 10^-5 M

Now,

molarity = moles of solute/volume of solvent in Liters

            = (mass of protein/molar mass)/volume

4.09 * 10^-5 moles/L = (1.0 g/molar mass)/0.1 L

Molar mass of protein = 2.445 * 10^5 g/mole

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Irina18 [472]

Mass of KNO₃ : = 40.643 g

<h3>Further explanation</h3>

Given

28.5 g of K₃PO₄

Required

Mass of KNO₃

Solution

Reaction(Balanced equation) :

2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃

mol K₃PO₄(MW=212,27 g/mol) :

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Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :

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= 6/2 x 0.134

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