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zhenek [66]
3 years ago
15

1.0g of a protein is dissolved in 100 ml of distilled water. The resulting solution has an osmotic pressure of .001 atm. What is

the molecular weight of the protein? Use r = .0821 l atm-1 mol-1.
Chemistry
1 answer:
Svetlanka [38]3 years ago
7 0

The osmotic pressure π, is related to concentration i.e. molarity (M) through the following equation:

π = MRT ------(1)

where R = gas constant = 0.0821 L atm/mol-K

T = temperature (let us assume 25 C = 25 + 273 = 298 K)

M = π/RT = 0.001/0.0821 * 298 = 4.09 * 10^-5 M

Now,

molarity = moles of solute/volume of solvent in Liters

            = (mass of protein/molar mass)/volume

4.09 * 10^-5 moles/L = (1.0 g/molar mass)/0.1 L

Molar mass of protein = 2.445 * 10^5 g/mole

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Answer:

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For the initial conditions :

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and for the final conditions:

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Assuming V₂ = V₁ and  dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂  / ( n₁ R T₁)      then  P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

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6 0
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The equilibrium reaction can be characterized by an equilibrium constant, which is the ratio of the concentration of the products by the concentration of the reactants.

Because the constant K is extremely large (10¹³) we can conclude that the concentration of the product will be greater than the concentration of the reactant, in the equilibrium. It means that the concentration of the enol will be greater.

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