Q1-Write Lewis diagram for a)Ne,b)Sb(Z=51),c)Rn,d)a neutral atom with 9 electrons

Chemistry

1 answer:

skelet666 [1.2K]3 years ago

3 0

Explanation: Lewis structure is defined as the structure in which the element is shown with its valence electron represented as dots.

Valence electrons are the electrons present in the last shell.

For Ne: The atomic number is 10. Valence electronic configuration is $[He]2s^22p^6$

Number of valence electrons = 8

For Sb: The atomic number if 51. Electronic configuration is $[Kr]4d^{10}5s^25p^3$

Number of valence electron = 5

For Rn: The atomic number is 86. Electronic configuration is $[Xe]4f^{14}5d^{10}6s^26p^6$

Number of valence electrons = 8

For a neutral atom with 9 electrons : The atomic number for this element is 9 and the element is Fluorine (F). Electronic configuration is $[He]2s^22p^5$

Number of valence electrons = 7

The lewis structures of all the elements are shown in the image attached.

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