Question

Q1-Write Lewis diagram for a)Ne,b)Sb(Z=51),c)Rn,d)a neutral atom with 9 electrons

Answer 1

Explanation: Lewis structure is defined as the structure in which the element is shown with its valence electron represented as dots.

Valence electrons are the electrons present in the last shell.

• For Ne: The atomic number is 10. Valence electronic configuration is $[He]2s^22p^6$

Number of valence electrons = 8

• For Sb: The atomic number if 51. Electronic configuration is $[Kr]4d^{10}5s^25p^3$

Number of valence electron = 5

• For Rn: The atomic number is 86. Electronic configuration is $[Xe]4f^{14}5d^{10}6s^26p^6$

Number of valence electrons = 8

• For a neutral atom with 9 electrons : The atomic number for this element is 9 and the element is Fluorine (F). Electronic configuration is $[He]2s^22p^5$

Number of valence electrons = 7

The lewis structures of all the elements are shown in the image attached.