All categories

2 years ago

If m x=49, y =41 x=90, y=49 x=90 y=41 x=41 y=49

Mathematics

1 answer:

a_sh-v [17]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Simplify: <br>{(12)^1 + (13)^-1}/[(1/5)^-2 × {(1/5)^-1 + (1/8)^-1}^-1]

CaHeK987 [17]

Step-by-step explanation:

$\underline{\underline{\sf{➤\:\:Solution}}}$

$\sf \dashrightarrow \: \dfrac{ \left(\left(12 \right)^{ - 1} + \left(13 \right)^{ - 1} \right) }{\left( \dfrac{1}{5}\right) ^{ - 2} \times\left( \left( \dfrac{1}{5} \right) ^{ - 1} +\left( \dfrac{1}{8} \right) ^{ - 1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{1}{12} + \dfrac{1}{13} \right) }{\left( \dfrac{5}{1}\right) ^{ 2} \times\left( \dfrac{5}{1} + \dfrac{8}{1} \right) ^{ - 1}}$

LCM of 12 and 13 is 156

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{1 \times 13 = 13}{12 \times 13 = 156} + \dfrac{1 \times 12 = 12}{13 \times 12 = 156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{5 + 8}{1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{13}{156} + \dfrac{12}{156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{13}{1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{13 + 12}{156} \right) }{\ \dfrac{25}{1} \times\dfrac{1}{13} }$

$\sf \dashrightarrow \: \dfrac{25}{156} \div \dfrac{25}{13}$

$\sf \dashrightarrow \: \dfrac{ \cancel{25}}{156} \times \dfrac{13}{ \cancel{25} }$

$\sf \dashrightarrow \: \dfrac{13}{156}$

$\sf \dashrightarrow \: \dfrac{1}{12}$

$\sf \dashrightarrow \: Answer = \underline{\boxed{ \sf{ \dfrac{1}{12} }}}$

━━━━━━━━━━━━━━━━━━━━━━━━

$\underline{\underline{\sf{★\:\:Laws\:of\: Exponents :}}}$

$\sf \: 1^{st} \: Law = \bigg( \dfrac{m}{n} \bigg)^{a} \times \bigg( \dfrac{m}{n} \bigg)^{b} = \bigg( \dfrac{m}{n} \bigg)^{a + b}$

$\sf 2^{nd} \: Law =$

$\sf Case : (i) \: if \: a > b \: then, \bigg( \dfrac{m}{n}\bigg) ^{a} \div \bigg( \dfrac{m}{n}\bigg)^{b} = \bigg( \dfrac{m}{n}\bigg)^{a - b}$

$\sf Case : (ii) \: if \: a < b \: then, \bigg( \dfrac{m}{n}\bigg) ^{a} \div \bigg( \dfrac{m}{n}\bigg)^{b} = \dfrac{1}{\bigg( \dfrac{m}{n}\bigg)^{b - a}}$

$\sf \: 3^{rd} \: Law = \bigg\{ \bigg( \dfrac{m}{n} \bigg)^{a} \bigg\}^{b} = \bigg( \dfrac{m}{n} \bigg)^{a \times b} =\bigg( \dfrac{m}{n} \bigg)^{ab}$

$\sf \: 4^{th} \: Law = \bigg( \dfrac{m}{n} \bigg)^{ - 1} = \bigg( \dfrac{n}{m} \bigg) =\dfrac{n}{m}$

$\sf \: 5^{th} \: Law = \bigg( \dfrac{m}{n} \bigg)^{0} = 1$

3 0

2 years ago

Read 2 more answers

a culture started with 6,000 bateria after 6 hours,it grew to 7,200 .predict how many bacteria will be present after 17 hours ro

Genrish500 [490]

Answer:

10058

Step-by-step explanation:

The equation is of the form

y = ab^x

Where a is the initial value, y is the final amount and x is the time

y = 6000 b^x

7200 = 6000 b^6

Divide each side by 6000

7200/6000 = b^6

1.2 = b^6

Take the 6th root on each side

1.2 ^ 1/6 = b^6 ^ 1/6

1.030853321 = b

y = 6000 (1.030853321) ^ x

Let x = 17

y = 6000 (1.030853321) ^ 17

y=10057.68696

Rounding to the nearest whole number

y = 10058

7 0

2 years ago

Read 2 more answers

Hello i really need help, please help me. thank you :(

vlabodo [156]

Answer:

12/13

Step-by-step explanation:

The cosine of an angle in a triangle can be calculated as a relation between the adjacent side and the hypothenuse. So, in this case the adjacent side of θ is 24 and the hypothenuse is 26.

Then:

cos(θ) = 24/26 = 12/13

6 0

2 years ago

Read 2 more answers

Please Assist!<br>What is the answer to this question???<br>

Phoenix [80]

Answer:

$(-5,\frac{1}{2} )$

Step-by-step explanation:

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

Simply plug in your coordinates into the midpoint formula to find midpoint:

R(-2, 3)

S(-8, -2)

$(\frac{-2+-8}{2},\frac{3+-2}{2} )$

$(\frac{-10}{2},\frac{1}{2} )$

$(-5,\frac{1}{2} )$

3 0

2 years ago

Estimate it as a whole number

denis-greek [22]

Answer:

Step-by-step explanation:

First, you do the subtraction 120-21.4 which is 98.7. So since you know its x^7, the number isn't going to be big. By guessing and checking, we start with 2. 2^7 is 128. We know that 1^7 would just be 1, so the closest whole number would be two.

7 0

3 years ago