What is the perimeter of the isosceles right triangle with hypotenuse 10?
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Answer:
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Step-by-step explanation:
Well, the center origin of the circle is given (h,k) = (5,7).
We have to find our radius as they gave us a point. from origin to the edge of the circle.
Using the formula: (x - h)^2 + (y - k)^2 = r^2
Plug in our (h,k) = (5,7) and (x,y) = (10,19) to solve for radius.
(x - h)^2 + (y - k)^2 = r^2
(10 - (5))^2 + (19 - (7)^2 = r^2
(5)^2 + (12)^2 = r^2
25 + 144 = r^2
r^2 = 169
r = 13