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maks197457 [2]
3 years ago
10

5. What value of makes the statement true? cos e = sin( 0/3 -10)​

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

and

Step-by-step explanation:

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What is the length of the the midsegment of a trapezoid with<br> a<br> bases of length 18 and 28?
Gwar [14]

Answer:

Step-by-step explanation:

5 0
2 years ago
800 jerseys 6 medium jerseys what percent of the jerseys is medium?
dimulka [17.4K]

The percent of the jerseys :

6 : 800 = 0,75%

7 0
3 years ago
This parabola has<br> x-intercepts
slega [8]

Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

y=-16x^{2} +32x-10

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

so

For y=0

-16x^{2} +32x-10=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16x^{2} +32x-10=0        

so

a=-16\\b=32\\c=-10

substitute in the formula

x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}

x=\frac{-32(+/-)\sqrt{384}} {-32}

x=\frac{-32(+/-)8\sqrt{6}}{-32}

x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec

x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec

therefore

This parabola has two x-intercepts representing the times when the dolphin's height above water is zero feet

8 0
3 years ago
Read 2 more answers
If f(x) = -3x - 5 and g(x) = 4x - 2, find (f+ g)(x).
STALIN [3.7K]

Answer:

-40x

Step-by-step explanation:

f(x) =-3x-5

g(x) =4x-2

(f+g)(x) =?

now,

f(g(x))

=f(4x-2)

=-3×4x-2-5

=-10×4x

=-40x

7 0
2 years ago
Overline MD cong overline LS additional information is necessary to show that triangle MTD cong triangle LGS by SSS?
aivan3 [116]

Answer:

TD \cong GS

Step-by-step explanation:

See comment for complete question

Given:

TM \cong GL

MD \cong LS

Required

The information that shows \triangle MTD \cong \triangle LGS by SSS

By SSS implies that, the three sides of both triangles are congruent

Already, we have:

TM \cong GL

MD \cong LS

The third side of \triangle MTD is TD

The third side of \triangle LGS is GS

So, for both to be congruent by SSS, the third sides must be congruent

i.e.

TD \cong GS

4 0
2 years ago
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