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larisa [96]
3 years ago
10

Which points are exactly 10 units from the point (–8, –2)? Check ALL that apply.

Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

The points that are exactly 10 units from the point (–8, –2) are (2, –2)  and (–8, 8).

Step-by-step explanation:

The distance formula is;

                               d= \sqrt{( x_{2}-x_{1} )^{2}-(y_{2} -y_{1} )^{2}   }

So for distance between: (–8, –2)  and (2, –2) is:

                             d=  \sqrt{( 2-(-8))^{2}-(-2 -(-2) )^{2}   }

                             d= \sqrt{100}

                            d= 10 unit

Similarly for distance between: (–8, –2) and (–8, 8) is,

                                d=  \sqrt{( -8-(-8))^{2}-(8 -(-2) )^{2}   }

                               d= \sqrt{100}

                               d= 10 unit

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VashaNatasha [74]

Answer:

x=-3

Step-by-step explanation:

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8 + 4x = -4

                   subtract 8 from both sides

4x = -12

                   divide both sides by 4

x = -3

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3 years ago
Solve for x.<br><br> 4x + 3 = 35
anzhelika [568]

Answer:

x = 8

Step-by-step explanation:

4x + 3 = 35

subtract 3 from both sides

4x + 3 - 3 = 35 - 4

4x = 32

divide both sides by 4

4x / 4 = x

32/4 = 8

we're left with x = 8

6 0
2 years ago
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What is the area of the shaded portion of the circle?
iren2701 [21]

Answer:

1st option

Step-by-step explanation:

the area of the shaded portion is calculated as

area of sector - area of white Δ

area of sector = area of circle × fraction of circle

                        = πr² × \frac{90}{360} ( r is the radius )

                        = π × 8² × \frac{1}{4}

                       = 64π × \frac{1}{4}

                       = 16π in²

area of Δ = \frac{1}{2} bh ( b is the base and h the perpendicular height )

here b = h = 8

area of Δ = \frac{1}{2} × 8 × 8 = \frac{1}{2} × 64 = 32 in²

then

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2 years ago
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Answer:

3 pens.

Step-by-step explanation:

x+y=7 where x is # of pens and y =# of pencils

3x + 2y= $18

from first equation, x=-y+7 so substitute that into other equation

3(-y+7)+2y=18

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now replace y =3 into first equation

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3 years ago
Gretchen made a paper cone to hold a gift for a friend. The paper cone was 16 inches high and had a radius of 4 inches. Find the
tekilochka [14]

Answer:

268.0 in²

Step-by-step explanation:

refer to attached graphic as reference

volume of cone, V = (1/3) πr²h

in our case, we are given r = 4" and h = 16"

substituting this into equation:

V = (1/3) πr²h

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