Answer:
<u>Answer</u><u>:</u><u> </u><u>There</u><u> </u><u>are</u><u> </u><u>9</u><u>1</u><u>8</u><u> </u><u>pupils</u><u> </u><u>now</u><u>.</u>
• Rise in percentage:
• let current number of pupils be n
4x2 + 4x =- 4 Find the solutions to the Quadratic equation.
1 answer:
You might be interested in
Yes, this is fun
remember the roots of a polynomial is
P(x)=(x-r1)(x-r2)...(x-rn)
so we have 5th degreee, means all exponents shoud add to 5
leading coeficient of 1, that means
P(x)=1x^n+bx^(n-1)...zx^0
means highest power coefience it 1
roots of multiplicity 2 at x=2 and x=0, means those roots show up 2 times each
root at x=2 means (x-2), it has multiplicity 2 so (x-2)^2
root at x=0 means (x-0), it has multiplicyt 2 so (x-0)^2
last one, multiplicity 1 and root at x=-4
(x-(-4))^1=(x+4)
so the polynomial is
remember the roots of a polynomial is
P(x)=(x-r1)(x-r2)...(x-rn)
so we have 5th degreee, means all exponents shoud add to 5
leading coeficient of 1, that means
P(x)=1x^n+bx^(n-1)...zx^0
means highest power coefience it 1
roots of multiplicity 2 at x=2 and x=0, means those roots show up 2 times each
root at x=2 means (x-2), it has multiplicity 2 so (x-2)^2
root at x=0 means (x-0), it has multiplicyt 2 so (x-0)^2
last one, multiplicity 1 and root at x=-4
(x-(-4))^1=(x+4)
so the polynomial is
Answer:
The common ratio of the geometric sequence is:
Step-by-step explanation:
A geometric sequence has a constant ratio 'r' and is defined by
where
- aₙ is the nth term
- a₁ is the first term
- r is the common ratio
Given the sequence
Compute the ratios of all the adjacent terms:
The ratio of all the adjacent terms is the same and equal to
Therefore, the common ratio of the geometric sequence is: