We have the following points and their coordinates:
We must compute the distance ST between them.
The distance ST between the two points is given by:
![ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},](https://tex.z-dn.net/?f=ST%3D%5Csqrt%5B%5D%7B%28x_S-x_T%29%5E2%2B%28y_S-y_T%29%5E2_%7B%7D%7D%2C)
where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.
Replacing the coordinates of the points in the formula above, we find that:
![\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ST%3D%5Csqrt%5B%5D%7B%28-3_%7B%7D-%28-2%29_%7B%7D%29%5E2%2B%2810_%7B%7D-3_%7B%7D%29%5E2_%7B%7D%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B1%5E2%2B7%5E2%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B50%7D%5Ctext%7B.%7D%20%5Cend%7Bgathered%7D)
Answer: ST = √50
6m + 6m + 15m + 15m = 42m
no 40m will not be enough
Answer:
61
Step-by-step explanation:
and let c looks to be a right angle
Answer:
january = 10/20 = 1/2
februry = 7/14 = 1/2
so, we conclude that the auto dealership didn't have a lower ratio, since the ratio is equal in both months.
<em>hope it helps :)</em>
<em />
The first one is 135 per hour if you barely went 90 miles in a hour in a half, and the second one it is 1/3+1/3+1/3 you add 2 more thirds so it means you add 2 forths 1/4/+1/4+1/4=3/4 so you paint 3/4's of the wall
