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2 years ago

One case can hold 3 boxes.Each box can hold 3 binders.How man cases are needed to hold 126 binders?

2 answers:

8 0

14 because if 1 case held 3 boxes and 3 boxes held 3 Binders, that means u would have to divide 3 by 126 which equals 42 and u would have to divide that by 3 which equals 14.

stealth61 [152]2 years ago

7 0

14 because 126 ÷3=42 and 42÷3 =14

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HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

2 years ago

A submarine is searching for underwater features. It is accompanied by a small aircraft

Ivanshal [37]

Answer:

255 m

Step-by-step explanation:

From the given question, the surface of the water body is the reference point. And this point is assumed to be 0, so that any distance above it is positive, and any distance below is negative. This is synonymous to the number line system.

Thus,

For the aircraft, its height = +200 m

For the submarine, its depth = -55 m

So that the difference between the submarine and aircraft can be determined as;

200 - (-55)

= 200 + 55

= 255 m

The distance between the submarine and aircraft is 255 m.

7 0

2 years ago

A basketball team played six games. In those games, the team won by 8 points, lost by 25,won by 9, won by 10,lost by 1, and won

Aneli [31]

Answer:

about 10 without a remainder of 4

Step-by-step explanation:

So, add up the number and divide by how many number you have (definition of mean). 8 + 25 + 9 + 10 + 11 + 1 all divide by 6 (since there are 6 numbers)

8 + 25 + 9 + 10 + 11 + 1 is 64.

64/6 is about 10 without a remainder of 4

4 0

2 years ago

What are the coordinates of point BBB on \overline{AC} AC start overline, A, C, end overline such that the ratio of ABABA, B to

Nady [450]

I think it’s gonna be C

3 0

2 years ago

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Question 14 of 17

kipiarov [429]

Answer:d

Step-by-step explanation:

I’m smart trust me

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2 years ago