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serious [3.7K]
3 years ago
14

One case can hold 3 boxes.Each box can hold 3 binders.How man cases are needed to hold 126 binders?

Mathematics
2 answers:
Len [333]3 years ago
8 0
14 because if 1 case held 3 boxes and 3 boxes held 3 Binders, that means u would have to divide 3 by 126 which equals 42 and u would have to divide that by 3 which equals 14.
stealth61 [152]3 years ago
7 0
14 because 126 ÷3=42 and 42÷3 =14

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Serhud [2]
So lets get to the problem 

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<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

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<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
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<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
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<span>Substitute the above values with the following... These should be memorized </span>
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<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
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Step-by-step explanation:

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