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frozen [14]
3 years ago
7

*PLEASE ANSWER!!! THANK YOU!!*

Mathematics
1 answer:
dusya [7]3 years ago
4 0

Answer:

a.

Step-by-step explanation:

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Which of these is a zero of the polynomials p(y) = 3y^3 - 16 y - 8? * - 8 0 2 - 2
borishaifa [10]

The zero of polynomials is -2. The polynomials is p(y) = 3y^{3} - 16 y - 8.

According to the question,

The polynomials is p(y) = 3y^{3} - 16 y - 8. In order to find the zero of polynomials only if we substitute the value and polynomials become zero.

p(-2) = 3(-2)^{3} - 16 (-2) - 8

= 3(8) + 32 -8

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Hence, the zero of polynomials is -2. The polynomials is p(y) = 3y^{3} - 16 y - 8.

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brainly.com/question/1720316

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