The problem above can be modelled as shown in the graph below
At
, the height of the water from the ground is
At
Determine the solution 9m+5=-13;-2, -3, -4
1 answer:
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Answer:
Quadrant 4
Step-by-step explanation:
If the given angle was positive, then we go clockwise.
But it's negative so we go counterclockwise.
An alternative way of graphing
Quadrant 1 is 0-90°
Quadrant 2 is 90-180°
Quadrant 3 is 180-270°
Quadrant 4 is 270-360°
Subtract the given angle by 360 until no longer possible
750 - 360 = 390 390 - 360 = 30
Remember that this was originally a negative angle
Instead of going clockwise to quadrant 1, we go counterclockwise to quadrant 4, ending up at 330°
Answer:13.1
Step-by-step explanation:
Area equation:S=