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3 years ago

Can someone tell me the answer to this please???

Mathematics

1 answer:

romanna [79]3 years ago

4 0

Measure of x is 74 degrees

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Anderson’s Nursery was choosing between two different greenhouses. Which statements are true about the greenhouses? Select two o

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4 years ago

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What are the values of the three Trigonometric ratio for angle L, in simplest form

bulgar [2K]

$\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\tan\theta=\dfrac{opposite}{adjacent}$

$opposite=20\\\\adjacent=15\\\\hypotenuse=25\\\\\sin L=\dfrac{20}{25}=\dfrac{4}{5}\\\\\cos L=\dfrac{15}{25}=\dfrac{3}{5}\\\\\tan L=\dfrac{20}{15}=\dfrac{4}{3}$

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4 years ago

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In the Roman republic senators implemented the majority of laws or oligarchs were voted in the control legal system legislation

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The correct answer for this question is this one: "oligarchs were voted in and controlled the legal system" In the Roman republic oligarchs were voted in and controlled the legal system. Hope this helps answer your question and have a nice day ahead.

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4 years ago

The exterior angle of a triangle is 164 degree and one

nataly862011 [7]

Answer:

• Let the other interior angle be x

${ \rm{x + 98 \degree = 164\degree}} \\ \\ { \rm{x = 164\degree - 98\degree}} \\ \\ { \boxed{ \rm{x = 66\degree}}}$

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3 years ago

Given triangle ABC, which equation could be used to find the measure of ∠B? right triangle ABC with AB measuring 6, AC measuring

rjkz [21]

Answer:

$cos B = \dfrac{2\times \sqrt5}{5}$ is the correct answer.

Step-by-step explanation:

We are given a right angled $\triangle ABC$ with the side measurements as:

AB = 6

AC = 3

BC = 3 $\sqrt5$

In a right angled triangle, the angle of $90^\circ$ is the <em>largest angle and the side opposite to the right angle is the largest.</em>

We are given that the side BC = 3 $\sqrt5$ which has a value greater than 6 which means side BC is the largest side.

And angle opposite to BC is $\angle A$ is the largest i.e.

$\angle A=90^\circ$

Please refer to the attached image for the given dimensions of the triangle.

Now, we can apply trigonometric rules to easily find out the value of $\angle B$

$cos \theta = \dfrac{Base}{Hypotenuse}\\OR\\cos B = \dfrac{AB}{BC}\\\Rightarrow cos B = \dfrac{6}{3\sqrt5}\\\Rightarrow cos B = \dfrac{2}{\sqrt5}\\\Rightarrow cos B = \dfrac{2\times \sqrt5}{\sqrt5 \times \sqrt5}\\\Rightarrow cos B = \dfrac{2\times \sqrt5}{5}$

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3 years ago