Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
There is no box’s also give me brainliest answer
Before we do any solving, we need to simplify both sides.
On the left, we can simplify -2x + 3x - 5 to x - 5.
On the right, we can simplify 6 - 21 to -16.
So we have x - 5 = -16.
Solving from here, we add 5 to both sides to get x = -11.
Answer:
3
Step-by-step explanation:
Let x = # of boxes of felt-tip pens.
(x)(3.44)+(4x)(4.41) = 63.24
21.08x = 63.24
x = 3
Because x = 3, the man bought 3 boxes of felt-tip pens and 12 boxes of ballpoint pens.
14.6969385 lies between 14 and 15.
I hope it's right! Virtually slap me if it is not.
