(2x10^3) x (4x10^4) = 8x10^1
Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
<h3>
Answer: 5</h3>
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One method is to plot the points P(3,6) and Q(7,3) on the same xy grid. Plot a third point R at (3,3). See the diagram below.
A right triangle forms in which we can find the legs PR = 3 and RQ = 4. The hypotenuse is found through the pythagorean theorem.
a^2+b^2=c^2
3^2+4^2 = c^2
9+16 = c^2
c^2 = 25
c = sqrt(25)
c = 5
This is the length of PQ
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Or you can use the distance formula which is effectively using the pythagorean theorem just in a slightly different format (though it may not be obvious).