An example of an Observational Study is

Explain what could be done to reduce the number of deaths by infectious diseases worldwide.

Zielflug [23.3K]

Answer:

vaccines.

Explanation:

5 0

3 years ago

Read 2 more answers

5. Which of the descriptions below best describes photosynthesis?

Ganezh [65]

Answer:

i think d but not too sure.

Explanation:

I think it is either d or b but pretty sure d

5 0

3 years ago

You are researching a cytoplasmic protein associated with a nerve disorder. The native form of the enzyme appears to be globular

kherson [118]

Answer:

This signifies that the protein primarily comprises multiple polypeptide chains connected together with the help of disulfide bonds. The enzymes may be found in the form of dimers, trimers, or tetramers. Various examples of dimers, trimers, and tetramer proteins are known, of them, NEMOs dimers are considered to be held by disulfide bonds.

Thus, it can be hypothesized that the enzyme under examination is a multimer held in combination by disulfide bonds, with each comprising catalytic sites. On breaking of disulfide bonds, the enzyme dissociates into its many single units.

This illustrates the reduction in catalytic activity. Each active site in a single unit will work, however, at a gradual rate. This also shows detection of multiple globular proteins after disulfide reduction.

8 0

2 years ago

A patient presents with low copper. which portion of cellular respiration would suffer?

Alex73 [517]

Copper deficiency is a rare disease that leads to hematological disorders. It is an essential trace element. It is an essential part of some enzymes (c0-factor) that plays role in cellular respiration. Copper is also an anti-oxidant that scavenges free radicals. In case of cellular respiration copper is responsible for electron transfer of oxygen.

6 0

3 years ago

14). During the early 1700’s, a small group of pacifist Protestants fled Germany to avoid religious persecution. This group, the

abruzzese [7]

A) In the Dunker population, the frequency of IB allele is 0.3 and the frequency of i allele is 0.4. In the general population, the frequency of IB allele is 0.1 and the frequency of i allele is 0.5.

If:
$I^{A}$ - the frequency of IA allele
 $I^{B}$ - the frequency of IB allele
 $i$ - the frequency of i allele

Then:
 $I^{A} I^{A}$ + $I^{A} i$ - the frequency of individuals with A blood type
 $I^{B} I^{B}$ + $I^{B} i$ - the frequency of individuals with B blood type
 $ii$ - the frequency of individuals with O blood type

Let's first take a look on the Dunker population:
$I^{A} = 0.3$
$ii=0.16
$

Since there is only one possible genotype for O individuals - ii - the frequency of the allele i is square root of the frequency of O individuals:
 $i= \sqrt{ii}$
⇒ $i = \sqrt{0.16}$
⇒ $i=0.4$

Now, we have the frequencies of two alleles ( $I^{A}$ and $i$ ). To calculate the frequency of $I^{B}$ allele, we will use the formula:
 $I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
⇒ $I^{B} = 1-0.3-0.4$
⇒ $I^{B} = 0.3$

Now, in the general population:
$I^{A} = 0.4$
$ii=0.25$

Similarly to the work for the Dunker population:
 $i= \sqrt{ii}$
⇒ $i = \sqrt{0.25}$
⇒ $i=0.5$

$I^{A} + I^{B} + i = 1$
⇒ $I^{B} = 1- I^{A} - i$
⇒ $I^{B} = 1-0.4-0.5$
⇒ $I^{B} = 0.1$


b) A founder effect is a result of geographical separation of a few individuals from the original population. Those founding individuals will form a new population. The Dunker population was not only geographically separated, but also genetically. The group interbreeding was present resulting in increasing those allele frequencies that were the most common in the founding population. In this case, the most individuals from the founding population had B blood type.

6 0

3 years ago